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Daniel [21]
3 years ago
15

Can ya'll help me pls

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

The answer is 280 I believe or C but I think A

Step-by-step explanation: I'm not 100% though

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Please answer correctly !!!!!!!!!!!!!! Will Mark Brianliest !!!!!!!!!!!!!!!!!!!
alexgriva [62]

Answer:

x = 30

Step-by-step explanation:

well from the theorem we have

\frac{15}{3}=\frac{x}{6}

yes i know you could say that the right way is

\frac{3}{15}=\frac{6}{x}

well if you notice they are the same only that in my way the x is in the numerator which means it will be far easier to know it's value :)

so

\frac{15}{3}=\frac{x}{6}\\\\5=\frac{x}{6}\\\\6[5]=6[\frac{x}{6}]\\\\30=x

8 0
3 years ago
Can someone help me on 12,13,14 :)
Stels [109]

Answer:

m∠XYZ = 166

AB = 2√5

Modpoint (1 , 5)

Step-by-step explanation:

Look at the photo below for the details.

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4 0
3 years ago
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alekssr [168]

Answer:

25 Meter

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Which value of x from the set {5,6,7,8} makes this equation true?<br><br> 3x = 24
N76 [4]
The answer is 8 because when you replace x by 8 it equals 24
3 0
3 years ago
A metallurgist has one alloy containing 32% copper and another containing 65% copper. How many pounds of each alloy must he use
kompoz [17]

Answer:

<h2>30.67 pounds of 32% copper alloy and 10.33 pounds of 65% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 32% copper and the second alloy contains 65% alloy.

We wish to make 44 pounds of a third alloy containing 42% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 44\text{ }pounds=x+y        -(i)

      Total weight of copper = 42\%\text{ of 44 pounds = }32\%\text{ of }x\text{ pounds + }65\%\text{ of }y\text{ pounds }

       \dfrac{42\times 44}{100}=\dfrac{32x}{100}+\dfrac{65y}{100}\\\\ 32x+65y=1848        -(ii)

       Subtracting 32 times first equation from second equation,

32x+65y-32x-32y=1848-32\times44\\33y=440\\y=13.333\text{ }pounds \\x=30.667\text{ }pounds

∴ 30.67 pounds of first alloy and 13.33 pounds of second alloy were used.

4 0
3 years ago
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