Let w and 2w-5 be the width and length. Then:
w(2w-5)=33
2w²-5w-33=0
(2w-11 )(w+3 )=0
w=11/2 or -3
If the width is 11/2 yd, then the length is 6 yds
☺☺☺☺
Answer:
Subtraction
Step-by-step explanation:
(4x^(5) - 8x) - (3x^(2) - 8x + 9) = 4
x^(
5) - 3
x^
(2) - 9
<h2>
Answer:</h2><h2>x = 13</h2><h2 /><h2>Hope this helps!!</h2>
C. Multiply and add
Cost = (3×21.99)+45.99
Cost = $111.96
If 1 classroom uses 16 sections, then 6 classrooms would use :
6 * 16 = 96 sections
and 14 classrooms would use : 14 * 16 = 224 sections
