Where would (aq) (s) go in Cr(NO3)3+K3PO4
1 answer:
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Answer:
See explanation below
Explanation:
When the bromine (Br₂) reacts in presence of FeBr₃ with the isopropylbenzene, the isopropylbenzene is a ring activator, therefore, it will promote the substitution in the ortho and para positions. However, as the Isopropyl is voluminic, the ortho position would have steric hindrance and hence, this product is not formed in greater proportions. Instead, the para position becomes more available to reaction, and this product is formed in majority.
The mechanism of reaction can be seen in the following picture, along with the products of the reaction
Hope this helps
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory:
- An acid is defined as a substance which looses donates protons and thus forming conjugate base
- A base is defined as a substance which accepts protons and thus forming conjugate acid.
Suppose acid Ha is getting dissociated in its solution and after dissociation it donates its proton to water molecule and forms conjugate base. Where as water (acting as a base) accepts protons and forms conjugate acid.
HA = Acid
= Base
= Conjugate base
= Conjugate acid
For example:
Sulfuric acid dissociating in its solution to form conjugate base and conjugate acid.
Sulfuric acid = Acid
= Base
= Conjugate base
= Conjugate acid