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Hitman42 [59]
4 years ago
13

Given a chemical equation, showing the dissociation of an acid in solution, be able to identify the "acid", the "base", the "con

jugate acid", and the "conjugate base"
Chemistry
1 answer:
Karo-lina-s [1.5K]4 years ago
3 0

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory:

  • An acid is defined as a substance which looses donates protons and thus forming conjugate base
  • A base is defined as a substance which accepts protons and thus forming conjugate acid.

HA+H_2O\rightarrow A^-+H_3O^+

Suppose acid Ha is getting dissociated in its solution and after dissociation it donates its proton to water molecule and forms conjugate base. Where as water (acting as a base) accepts protons and forms conjugate acid.

HA = Acid

H_2O = Base

A^- = Conjugate base

H_3O^+ = Conjugate acid

For example:

H_2SO_4+2H_2O\rightarrow SO_4^{2-}+2H_3O^+

Sulfuric acid dissociating in its solution to form conjugate base and conjugate acid.

Sulfuric acid  = Acid

H_2O = Base

SO_^{2-} = Conjugate base

H_3O^+ = Conjugate acid

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I think that electonegativity increases

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An aqueous solution 10 g of an optically pure substance diluted to 500ml with water and placed in a polarimeter tube 20 cm long.
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Explanation:

Formula to calculate specific rotation is as follows.

        Specific rotation ([\alpha]) = \frac{\alpha}{c} \times l

where,    \alpha = observed rotation

                   c = concentration in g/ml

                   l = path length in dm

It is given that,

             \alpha = -6.16^{o}    

               c = \frac{10 g}{500 ml} = 0.02 g/ml

              l = 20 cm = 2 dm   (as 1 dm = 10 cm)

Therefore, calculate the specific rotation as follows.

      Specific rotation ([\alpha]) = \frac{\alpha}{c} \times l

                        = \frac{-6.16^{o}}{0.02 g/ml} \times 2 dm

                        = -616^{o}

Thus, we can conclude that the specific rotation of this compound is -616^{o}.

7 0
3 years ago
An unknown compound has the following chemical formula: where stands for a whole number. Measurements also show that a certain s
anygoal [31]

The question is incomplete, the complete question is;

An unknown compound has the following chemical formula:  

N2Ox  

where x stands for a whole number.  

Measurements also show that a certain sample of the unknown compound contains 3.7 mol of oxygen and 2.45 mol of nitrogen.  

Write the complete chemical formula for the unknown compound.

Answer:

The complete formula of the compound is N2O3.

Explanation:

Given;

Number of moles of N = 2.45 moles

Number of moles of O = 3.7 moles

Chemical formula of unknown compound = N2Ox

From the ratio of the number of moles of N to O;

2/x = 2.45/3.7

2 * 3.7 = x * 2.45

x = 2 * 3.7/ 2.45

x =3

Hence the complete formula of the compound is N2O3.

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A gray whale can travelan average of 120<br> km per day as it migrates.
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25.0 mL of an LiOH solution were titrated with 29.15 mLof a 0.205 M H3PO4 solution to reach the equivalence point. What is the m
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Answer:

0.717 M LiOH

Explanation:

(Step 1)

Calculate the moles of H₃PO₄ using the molarity equation.

29.15 mL / 1,000 = 0.02915 L

Molarity = moles / volume (L)

0.205 M = moles / 0.02915 L

0.00598 = moles

(Step 2)

Convert moles H₃PO₄ to moles LiOH using the mole-to-mole ratio from reaction coefficients.

1 H₃PO₄ + 3 LiOH -----> Li₃PO₄ + 3 H₂O
^                ^

0.00598 moles H₃PO₄            3 moles LiOH
------------------------------------  x  --------------------------  =  0.0179 moles LiOH
                                                  1 mole H₃PO₄

(Step 3)

Calculate the molarity of LiOH using the molarity equation.

25.0 mL / 1,000 = 0.0250 L

Molarity = moles / volume (L)

Molarity = 0.0179 moles / 0.0250 L

Molarity = 0.717 M

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