1. 0.625 and 62.5%
2. Match 1 had 156 expert fighters (0.5 x 312), Match 2 had 110 expert fighters (0.4x275) Match 1 had more expert fighters by 46
Rewrite then factor as a difference of cubes:
1 - 64<em>x</em>³ = 1³ - (4<em>x</em>)³
= (1 - 4<em>x</em>) (1² + 4<em>x</em> + (4<em>x</em>)²)
= (1 - 4<em>x</em>) (1 + 4<em>x</em> + 16<em>x</em>²)
6m + 15m+ 20= 75
6m+ 15m= 75- 20
21m= 55
m= 55/21
m= 2.61
If the coins are selected without replacement, the probability of 2 dimes is:
The answer is 5/14.
Using the formula for a hypergeometric distribution, we get:
Answer:
1. 3x-4.7
2. 4x-11
3. 7x-5
4.4x-10
5. 3x-1
6. 8x-10
Step-by-step explanation:
1. 1x-1.2+2x-3.5
2. 5x-7-x-4
3. 28x+11-21x-16
4. 6x-7-2x-3
5. 5x-2-2x+1
6. 14x+11-6x-21
