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kotykmax [81]
3 years ago
11

Choose the balanced chemical equation below that best represents the following reaction:

Chemistry
1 answer:
suter [353]3 years ago
8 0

The balanced chemical equation :

NaHCO₃ + HCl → CO₂ + H₂O + NaCl

<h3>Further explanation</h3>

A balanced chemical reaction shows that the number of atoms of the reactant and the number of atoms of the product is the same

When baking soda (NaHCO3) reacts with hydrochloric acid (HCl), carbon dioxide bubbles (CO2) are created, along with water (H2O) and sodium chloride (NaCl) .

This statement shows that

Reactants (located to the left of the reaction)

Baking soda (NaHCO₃) and Hydrochloric acid (HCl)

product (located to the right of the reaction)

Carbon dioxide(CO₂),water  (H₂O) and Sodium chloride (NaCl).

So the reaction :

NaHCO₃ + HCl → CO₂ + H₂O + NaCl

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Which reactant will be used up first if 78.1g of o2 is reacted with 62.4g of c4h10?
dlinn [17]

Answer:

Reagent O₂ will be consumed first.

Explanation:

The balanced reaction between O₂ and C₄H₁₀ is:

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Then, by reaction stoichiometry, the following amounts of reactants and products participate in the reaction:

  • C₄H₁₀: 2 moles
  • O₂: 13 moles
  • CO₂: 8 moles
  • H₂O: 10 moles

Being:

  • C: 12 g/mole
  • H: 1 g/mole
  • O: 16 g/mole

The molar mass of the compounds that participate in the reaction is:

  • C₄H₁₀: 4*12 g/mole + 10*1 g/mole= 58 g/mole
  • O₂: 2*16 g/mole= 32 g/mole
  • CO₂: 12 g/mole + 2*16 g/mole= 44 g/mole
  • H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of reactants and products participate in the reaction:

  • C₄H₁₀: 2 moles* 58 g/mole= 116 g
  • O₂: 13 moles* 32 g/mole= 416 g
  • CO₂: 8 moles* 44 g/mole= 352 g
  • H₂O: 10 moles* 18 g/mole= 180 g

If 78.1 g of O₂ react, it is possible to apply the following rule of three: if by stoichiometry 416 g of O₂ react with 116 g of C₄H₁₀, 62.4 g of C₄H₁₀ with how much mass of O₂ do they react?

mass of O_{2} =\frac{416grams of O_{2}*62.4 grams ofC_{4}H_{10}   }{116 grams of C_{4}H_{10}}

mass of O₂= 223.78 grams

But 21.78 grams of O₂ are not available, 78.1 grams are available. Since you have less mass than you need to react with 62.4 g of C₄H₁₀, <u><em>reagent O₂ will be consumed first.</em></u>

3 0
3 years ago
2KClO3(s) =&gt; 2KCl(s) + 3O2(g) <br> is there an increase or decrease of entropy?
ValentinkaMS [17]

Answer:

Entropy increases

Explanation:

Entropy (S) is a measure of the degree of disorder.  For a given substance - say water - across phases the following is true ...

S(ice) < S(water) << S(steam)

For a chemical process, entropy changes can be related to increasing or decreasing molar volumes of gas from reactant side of equation to product side of equation. That is ...

if molar volumes of gas increase, then entropy increases, and

if molar volumes of gas decrease, then entropy decreases.

For the reaction                  2KClO₃(s) => 2KCl(s) + 3O₂(g)

molar volumes of gas =>       0Vm*            0Vm      3Vm

*molar volumes (Vm) apply only to gas phase substances. Solids and liquids do not have molar volume.

Since the reaction produces 3 molar volumes of O₂(g) product vs 0 molar volumes of reactant, then the reaction is showing an increase in molar volumes of gas phase substances and its entropy is therefore increasing.

3 0
3 years ago
Examine the drawing of a molecule. Each ring represents an atom of nitrogen (N). What's the chemical formula of this
Agata [3.3K]
You did not link an image of it so I can’t see the rings.
7 0
3 years ago
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3 0
3 years ago
Read 2 more answers
If solid ammonium fluoride (NH4F) is dissolved in pure water, will the solution be acidic, neutral, or basic?
Leokris [45]

Answer:

Dissolving NH4F in water will form a weak acidic solution.

Explanation:

That it is a weak acid solution means that it has a pH below 7 but close to the value, that is, it does not contain as many acids as those substances that are around a pH of 1 to 4, generally weak acids have a pH approximately 5 to 6

8 0
3 years ago
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