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Ket [755]
3 years ago
14

some components of ink are minimally attracted to the stationary phase and very soluble in the solvent. where are these componen

ts locatedon the filter paper during chromatography?
Chemistry
2 answers:
Trava [24]3 years ago
5 0
They’ll have moved the farthest, since the solvent is best at carrying those kinds of materials.
zubka84 [21]3 years ago
4 0

Explanation:

Chromatography is defined as technique for separating a mixture of chemicals which can be present in a liquid or gaseous phase.

These chemical components are separated with the help of a stationary medium on which these components travel at a different rates.

The stationary phase could be a TLC plate or silica gel. And, the mobile phase includes the solvent.

For example, in the given situation ink is our mobile phase. Since, some of the components of ink are soluble into the solvent.

Therefore, ink components will travel will the solvent to the top.

Thus, we can conclude that at the top these components located on the filter paper during chromatography.

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Why do most atoms form chemical bonds?
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3 years ago
Which of the following statements is true when considering temperature during a recrystallization? More than one answer may be c
Otrada [13]

Answer:

The correct answer is:

<em>(1) It is important that the sample is dissolved in just enough hot solvent. </em>

Explanation:

The process of recrystallization is important to eliminate the impurities and to obtain better crystals of the solid. The solvent used to perform the recrystallization must have a high dissolution power of the substance to be recrystallized and a low dissolution power of the impurities. This is in order to eliminate most impurities. Furthermore, <em>It is important that the sample is dissolved in just enough hot solvent </em>because this should be easy to remove after the recrystallization and the crystal should form easily when the solution cools. Also, it is better to add the hot solvent to solubilize the crystals and keep the impurities insoluble, instead of adding the cold solvent and heating the solution. Additionally, the process of cooling the solution must be done slowly to obtain large and fewer crystals. A fast ice-cooling will form smaller crystals.

4 0
3 years ago
A solution was made by dissolving 5.10 mg of hemoglobin in water to give a final volume of 1.00 ml. the osmotic pressure of this
Assoli18 [71]

The molecular weight of hemoglobin can be calculated using osmotic pressure

Osmotic pressure is a colligative property and it depends on molarity as

πV = nRT

where

π = osmotic pressure

V = volume = 1mL = 0.001 L

n = moles

R = gas constant = 0.0821 L atm / mol K

T = temperature = 25°C = 25 + 273 K = 298 K

Putting values we will get value of moles

moles=\frac{\pi V}{RT}=\frac{0.00195X0.001}{0.0821X298}mol

we know that

moles=\frac{mass}{molarmass}

Therefore

molarmass=\frac{mass}{moles}=\frac{5.10X10^{-3}g}{7.97X10^{-8}}=6.399X10^{4}g

5 0
3 years ago
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