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Ket [755]
3 years ago
14

some components of ink are minimally attracted to the stationary phase and very soluble in the solvent. where are these componen

ts locatedon the filter paper during chromatography?
Chemistry
2 answers:
Trava [24]3 years ago
5 0
They’ll have moved the farthest, since the solvent is best at carrying those kinds of materials.
zubka84 [21]3 years ago
4 0

Explanation:

Chromatography is defined as technique for separating a mixture of chemicals which can be present in a liquid or gaseous phase.

These chemical components are separated with the help of a stationary medium on which these components travel at a different rates.

The stationary phase could be a TLC plate or silica gel. And, the mobile phase includes the solvent.

For example, in the given situation ink is our mobile phase. Since, some of the components of ink are soluble into the solvent.

Therefore, ink components will travel will the solvent to the top.

Thus, we can conclude that at the top these components located on the filter paper during chromatography.

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3 years ago
A fixed amount of gas in a rigid container is heated from 300 k to 900 k, which of the following responses best describes what w
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Answer: Option d. pressure increase by a factor of 3

Explanation:

P1 = P

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P2 =?

Volume is constant.

P1/T1 = P2/T2

P/300 = P2/900

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2 years ago
Lithium β is a solid phase of lithium still unknown to science. The only difference between it and ordinary lithium is that Lith
pychu [463]

Answer:

The density of Lithium β is 0.5798 g/cm³

Explanation:

For a face centered cubic (FCC) structure, there are total number of 4 atoms in the unit cell.

we need to calculate the mass of these atoms because density is mass per unit volume.

Atomic mass of Lithium is 6.94 g/mol

Then we calculate the mass of four atoms;

= 4 .atoms*\frac{1.mole}{6.022 X10^{23} .atoms} *\frac{6.94g}{mole} = 4.6097 X10^{-23} g

⇒next, we estimate the volume of the unit cell in cubic centimeter

given the edge length or lattice constant a = 0.43nm

a = 0.43nm = 0.43 X 10⁻⁹ m = 0.43 X 10⁻⁹ X 10² cm = 4.3 X 10⁻⁸cm

Volume of the unit cell = a³ = (4.3 X 10⁻⁸cm)³ = 7.9507 X 10⁻²³ cm³

⇒Finally, we calculate the density of Lithium β

Density = mass/volume

Density = (4.6097 X 10⁻²³ g)/(7.9507 X 10⁻²³ cm³)

Density = 0.5798 g/cm³

3 0
3 years ago
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