Question

I have an unknown volume of gas at a pressure of 0.5 atm and a temperature of 325k if I raise the pressure to 1.2 atm, decrease the temperature to 320k, and measures the final volume to be 48 liters what was the initial volume of the gas?

Answer 1

Use the Equation of Clapeyron:

$\frac{P_1.V_1}{T_1}=\frac{P_2.V_2}{T_2}\\ \\ \frac{0.5V_1}{235}=\frac{1.2*48}{320}\\ \\ 320*0.5V_1=235*1.2*48\\ \\ V_1=\frac{235*1.2*48}{320*0.5}=84.5 liters$