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3 years ago

Solve the equation: 7(3x+2)=18-(x+48)

Mathematics

2 answers:

Reil [10]3 years ago

7 0

X=22.2

do the math (I just added this so its valid)

uranmaximum [27]3 years ago

5 0

7(3x + 2) = 18 - (x + 48)

Distribute on both sides. On the left side, multiply each term in parentheses by 7. On the right side, a negative sign to the left of parentheses is as if a -1 is there, and you must multiply everything inside the parentheses by -1.

7(3x + 2) = 18 -1(x + 48)

21x + 14 = 18 - x - 48

21x + 14 = -x - 30

22x = -44

x = (-44)/22

x = -2

Answer: x = -2

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A number cube is rolled 14 times and the results are recorded in the table.

Arlecino [84]

Answer:

Step-by-step explanation:

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3 years ago

Find (fºg)(1) f(x) = x² - 1 g(x) = √x A.0 B.1 C.4 √2 D. √8

Savatey [412]

Given:

The function are

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

To find:

The value of $(f\circ g)(1)$ .

Solution:

We have,

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

We need to find the value of $(f\circ g)(1)$ .

$(f\circ g)(1)=f(g(1))$ $[\because (f\circ g)(x)=f(g(x))]$

$(f\circ g)(1)=f(\sqrt{1})$ $[\because g(x)=\sqrt{x}]$

$(f\circ g)(1)=f(1)$

$(f\circ g)(1)=(1)^2-1$ $[\because f(x)=x^2-1]$

$(f\circ g)(1)=1-1$

$(f\circ g)(1)=0$

The value of $(f\circ g)(1)$ is 0.

Therefore, the correct option is A.

4 0

3 years ago

You are buying a party pack of chips for $14.50 with a 3% tax. How much do you pay in total?

myrzilka [38]

Answer:

Step-by-step explanation:

The answer is .50

6 0

3 years ago

Read 2 more answers

A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f

tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

= 180° - (45° + 120°)

= 180° - 165°

= 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

$\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}$

$\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

$\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

PR = $\frac{12\text{sin}(120)}{\text{sin}(15)}$

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0

3 years ago

What is 2.3e-5 because I don't know what it is.

astraxan [27]

0.000023 i hope that helps

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3 years ago