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3 years ago

Solve: (4.5 x 10^4)/ (300) Please and Thank you.

Mathematics

2 answers:

Stells [14]3 years ago

8 0

Answer:

150 plz brainliest

Step-by-step explanation:

10^4 = 10000

10000 (4.5) = 45,000

45,000/300 = 150

Volgvan3 years ago

3 0

(1): "x1" was replaced by "x^1".
(2): "4.5" was replaced by "(45/10)"
1.1 10 = 2•5
(10)4 = (2•5)4 = 24 • 54

45
(—— • (x(2^4•5^4))) ÷ 300
10

9
Simplify —
2

9
— • x10000) ÷ 300
2

9x10000
——————— ÷ 300
2

9x10000
Divide ——————— by 300
2

Final result :
3x10000
———————
200

You might be interested in

Corey is visiting the Jefferson

lutik1710 [3]

Answer:

Step-by-step explanation:

He wants to estimate the height of the statue of Thomas Jefferson. Corey stands so that his line of vision to the top and base of the statue form a right angle as shown in the diagram. ... So, the total height of the statue is about 159 + 68 or 227 inches, which is equivalent to 18 ft 11 in. ANSWER: 18 ft 11 in.

8 0

2 years ago

(20 points and brainlest to whoever answers correctly!!!)

Stells [14]

Answer:

y = -2/3x - 11

Step-by-step explanation:

Steps to find the perpendicular bisector:

1) Find the midpoint of line PQ

Midpoint formula: ( $\frac{x_{1} + x_{2} }{2} \\$ , $\frac{y_{1} + y_{2}}{2}$ )

Midpoint of line PQ = (6, -2)

2) Find the slope of line PQ

Slope formula: $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Slope of line PQ = 3/2

3) Find the negative reciprocal of the slope of PQ

To find the negative reciprocal just swap the numerator and denominator and add a negative sign. If it is already negative it will become positive.

In this case it will be -2/3

4) Write the equation of line PQ in slop-intercept form.

Slope-intercept form: y = mx + b

This is what it will look like for line PQ: y = $\frac{3}{2}$ x + b

5) Plug the points of the midpoint into the line and solve for the intercept (b)

This is what it will look like: -2 = $\frac{3}{2}$ (6) + b

-2 = 18/2 + b

-2 = 9 + b

-11 = b

6) Write the equation of the perpendicular bisector

m = the negative reciprocal of the slope of PQ = -2/3

This is what the equation will look like: y = -2/3x - 11

Hope this helped! Please give Brainliest!

5 0

3 years ago

Two soccer teams play 8 games in their season. The number of goals each team scored per game is listed below: Team X: 11, 3, 0,

Gre4nikov [31]

Answer:

C. Team Y’s scores have a lower mean value.

Step-by-step explanation:

We are given that Two soccer teams play 8 games in their season. The number of goals each team scored per game is listed below:

Team X: 11, 3, 0, 0, 2, 0, 6, 4

Team Y: 4, 2, 0, 3, 2, 1, 6, 4

Firstly, we will calculate the mean, median, range and inter-quartile range for Team X;

Mean of Team X data is given by the following formula;

Mean, $\bar X$ = $\frac{\sum X}{n}$

= $\frac{11+ 3+ 0+ 0+ 2+ 0+ 6+ 4}{8}$ = $\frac{26}{8}$ = 3.25

So, the mean of Team X's scores is 3.25.

Now, for calculating the median; we have to arrange the data in ascending order and then observe that the number of observations (n) in the data is even or odd.

Team X: 0, 0, 0, 2, 3, 4, 6, 11

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.} }{2}$

Here, the number of observations is even, i.e. n = 8.

So, Median = $\frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.} }{2}$

= $\frac{(\frac{8}{2})^{th} \text{ obs.} +(\frac{8}{2}+1)^{th} \text{ obs.} }{2}$

= $\frac{(4)^{th} \text{ obs.} +(5)^{th} \text{ obs.} }{2}$

= $\frac{2+3}{2}$ = 2.5

So, the median of Team X's score is 2.5.

Now, the range is calculated as the difference between the highest and the lowest value in our data.

Range = Highest value - Lowest value

= 11 - 0 = 11

So, the range of Team X's score is 11.

Now, the inter-quartile range of the data is given by;

Inter-quartile range = $Q_3-Q_1$

$Q_1=(\frac{n+1}{4} )^{th} \text{ obs.}$

= $(\frac{8+1}{4} )^{th} \text{ obs.}$

= $(2.25 )^{th} \text{ obs.}$

$Q_1 = 2^{nd} \text{ obs.} + 0.25[ 3^{rd} \text{ obs.} -2^{nd} \text{ obs.} ]$

= 0 + 0.25[0 - 0] = 0

$Q_3=3(\frac{n+1}{4} )^{th} \text{ obs.}$

= $3(\frac{8+1}{4} )^{th} \text{ obs.}$

= $(6.75 )^{th} \text{ obs.}$

$Q_3 = 6^{th} \text{ obs.} + 0.75[ 7^{th} \text{ obs.} -6^{th} \text{ obs.} ]$

= 4 + 0.75[6 - 4] = 5.5

So, the inter-quartile range of Team X's score is (5.5 - 0) = 5.5.

<u>Now, we will calculate the mean, median, range and inter-quartile range for Team Y;</u>

Mean of Team Y data is given by the following formula;

Mean, $\bar Y$ = $\frac{\sum Y}{n}$

= $\frac{4+ 2+ 0+ 3+ 2+ 1+ 6+ 4}{8}$ = $\frac{22}{8}$ = 2.75

So, the mean of Team Y's scores is 2.75.

Now, for calculating the median; we have to arrange the data in ascending order and then observe that the number of observations (n) in the data is even or odd.

Team Y: 0, 1, 2, 2, 3, 4, 4, 6

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.} }{2}$

Here, the number of observations is even, i.e. n = 8.

So, Median = $\frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.} }{2}$

= $\frac{(\frac{8}{2})^{th} \text{ obs.} +(\frac{8}{2}+1)^{th} \text{ obs.} }{2}$

= $\frac{(4)^{th} \text{ obs.} +(5)^{th} \text{ obs.} }{2}$

= $\frac{2+3}{2}$ = 2.5

So, the median of Team Y's score is 2.5.

Now, the range is calculated as the difference between the highest and the lowest value in our data.

Range = Highest value - Lowest value

= 6 - 0 = 6

So, the range of Team Y's score is 6.

Now, the inter-quartile range of the data is given by;

Inter-quartile range = $Q_3-Q_1$

$Q_1=(\frac{n+1}{4} )^{th} \text{ obs.}$

= $(\frac{8+1}{4} )^{th} \text{ obs.}$

= $(2.25 )^{th} \text{ obs.}$

$Q_1 = 2^{nd} \text{ obs.} + 0.25[ 3^{rd} \text{ obs.} -2^{nd} \text{ obs.} ]$

= 1 + 0.25[2 - 1] = 1.25

$Q_3=3(\frac{n+1}{4} )^{th} \text{ obs.}$

= $3(\frac{8+1}{4} )^{th} \text{ obs.}$

= $(6.75 )^{th} \text{ obs.}$

$Q_3 = 6^{th} \text{ obs.} + 0.75[ 7^{th} \text{ obs.} -6^{th} \text{ obs.} ]$

= 4 + 0.75[4 - 4] = 4

So, the inter-quartile range of Team Y's score is (4 - 1.25) = 2.75.

Hence, the correct statement is:

C. Team Y’s scores have a lower mean value.

4 0

3 years ago

1.1(1.6x+0.4)-0.44= -17.6

sertanlavr [38]

Answer:

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

−

10.975

5 0

3 years ago

Need help on this problem

faust18 [17]

Using an exponential function, it is found that:

For Country A, the doubling time is of 43 years.

For Country B, the growth rate is of 1.9% per year.

<h3>What is the exponential function for population growth?</h3>

The exponential function for population growth is given as follows:

$P(t) = P(0)e^{kt}$

In which:

P(t) is the population after t years.

P(0) is the initial population.

k is the exponential growth rate, as a decimal.

t is the time in years.

For Country A, we have that k = 0.016. The doubling time is t for which P(t) = 2P(0), hence:

$P(t) = P(0)e^{kt}$

$2P(0) = P(0)e^{0.016t}$

$e^{0.016t} = 2$

$\ln{e^{0.016t}} = \ln{2}$

$0.016t = \ln{2}$

$t = \frac{\ln{2}}{0.016}$

t = 43 years.

For Country B, P(36) = 2P(0), hence we have to solve for k to find the growth rate.

$P(t) = P(0)e^{kt}$

$2P(0) = P(0)e^{36k}$

$e^{36k} = 2$

$\ln{e^{36k}} = \ln{2}$

$36k = \ln{2}$

$k = \frac{\ln{2}}{36}$

k = 0.019.

For Country B, the growth rate is of 1.9% per year.

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

3 0

1 year ago