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Marina CMI [18]
3 years ago
6

Hey Im stuck on this question, can someone help?

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0
The third answer is correct
makvit [3.9K]3 years ago
4 0

Answer:3

Step-by-step explanation:

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If the discriminant, b^2-4ac is ___, a quadratic will have two real roots, two points of intersection with the x-axis.
den301095 [7]

If the discriminant, b² - 4ac is<u> positive</u>

<h3>How to complete the statement?</h3>

From the question, we have the following equation of discriminant

The discriminant (d) is calculated as

d = b² - 4ac

The solutions of a quadratic equation are dependent on the following conditions

  • If d = 0, the quadratic equation has 1 real solution
  • If d < 0, the quadratic equation has imaginary solutions
  • If d > 0, the quadratic equation has 2 different real solutions

This means that "d > 0, the quadratic equation has 2 different real solutions" implies that the discriminant is positive

Hence, the complete statement is (b) positive

Read more about discriminant at

brainly.com/question/64103

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6 0
11 months ago
How tall is the flagpole?
Fudgin [204]
51 ft is the answer

Explanation

The hight of the man divided by the hight of school ( which is unknown )

Equal

The length of the shadow of the man divided by the shadow of the school

Cross multiplication and find the value of unknown x which is 51... and ya
4 0
2 years ago
Simplify the expression:<br> -<br> 4t+<br> -<br> 7t+3–10t
Gekata [30.6K]

Answer:t+3

Step-by-step explanation:

4t+7t+3-10t

11t+3-10t

t+3

8 0
3 years ago
. Find the area of the shaded<br>region of the given figures:<br>5cm<br>5cm<br>15cm<br>20cm​
Flauer [41]
5cm ahahhaa easy omg wr have
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3 years ago
True or false? it's not possible to build a triangle with side lengths of 3 3 and 9
Anit [1.1K]
True

The two shorter lengths do not add up to more than the longest length. 3+3 is less than 9. Therefore, even if the two shorter lengths lay on top of the longer side, the two ends cannot meet to form a closed 3 sided figure
6 0
2 years ago
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