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3 years ago

Y= 2x+4

Mathematics

1 answer:

Vinil7 [7]3 years ago

6 0

Answer:

the answer is (-8,0)

Step-by-step explanation:

thats the right answer

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Whats the mean of 72+72+72+79+82+82+88?

creativ13 [48]

Answer:

78.1428571429

Step-by-step explanation:

6 0

3 years ago

In the most recent election, 19 percent of all eligible college students voted. If a random sample of 20 students were surveyed,

lora16 [44]

Answer:. This would be 0.81^20 for none of the 19=0.0148

Step-by-step explanation:With a tree diagram, there are two possibilities, one is ND from 1 D from 2, with probability (5/8)(2/5)=(1/4) and the other is (3/8)(3/5)=9/40 That would be 19/40 for the answer.

3. Poisson parameter lambda=5

for P(0), it is e^(-5)(5^0)/0! or e^(-5)=0.0067

for P(1), it is e^(-5)(5^1)/1! or 5e(-5)

The total probability is 6e^-5 or 0.0404

4. the mean is 1000 hours, so lambda is the reciprocal or 1/1000

the probability it will last <800 hours is 1-e^(-800*1/1000) or 1-e^(-.8)=0.5507

5. assume p=0.4 since it ca't be 4

sd is sqrt (np*(1-p))=sqrt (6*0.6=sqrt(3.6)=1.90

7 0

3 years ago

Can someone explain how to write an equality and how to solve one? I don't understand.

iragen [17]

Okay so the circle on the line plot, if it is empty In the middle it is > or < if it is solid it is ≤ ≥. In this case it not solid so it will be > or < . The plot is at -1 1/2 and is going positive. So it would be a > -1 1/2

7 0

3 years ago

Student/dashboard/home

DIA [1.3K]

Answer:

multiply by 2

Step-by-step explanation:

5x2=10

10x2=20

8 0

3 years ago

Read 2 more answers

Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa

Nataly_w [17]

Answer:

The first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

coefficient of $x^{2}$ in the expansion of $(2+x - x^{2})^{6}$ = (240 - 192) = 48

Step-by-step explanation:

$(2+x)^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})$

= $6_{C_{0}} \times x^{0} \times 2^{6} + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4}$ + terms involving higher powers of x