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vazorg [7]
2 years ago
13

PLS HELP!! You have a dog crate that will hold up to 40 pounds. You have 2 dogs and need to transport them using a crate. One do

g weighs 22.75 pounds and the other weighs 15.2 pounds. Will the crate hold both of them? Explain.
Mathematics
1 answer:
professor190 [17]2 years ago
5 0

Answer:

Yes.

Step-by-step explanation:

22.75 + 15.2 =?

22+15= 37

.75 +.2 = .95

37+.95 = 37.95

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4y+2x=180 solve for x and y
kirill [66]
There you go!! Hope it helps

5 0
2 years ago
WILL GIVE BRANLIEST!!!!!!!!!!!!!
Lunna [17]

Answer:

D is the answer

Step-by-step explanation:

6 0
2 years ago
Jack is getting balloons for his uncle's birthday party. He wants each balloon string to be 6 feet long. At the party store, str
SCORPION-xisa [38]

Answer:

110 yards of string

Step-by-step explanation:

Converting the feet of the string of 1 balloon to yard

1 foot = 1/3 yard

6 feet = x

x = 6 × 1/3 yard

x = 2 yard

Hence 1 balloon uses 2 yard of string

Since:

1 balloon = 2 yard of string

55 ballons = x

x = 55 × 2 yard of string

x = 110 yards of string

Hence, for 55 balloons he would need 110 yards of string.

6 0
2 years ago
Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.50ft.
Anarel [89]
Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59

Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm

Given that the density of air at room temperature is 0.00118g/cm^3, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg

Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 = 8.88 mg.</span>
7 0
2 years ago
Please explain how to do this, I'm using all my points<br><br>A. 40 L<br>B. 80 L<br>C. 4 L <br>D. 8L
exis [7]

Answer: choice A. 40 liters

====================================

Explanation:

x = number of liters of the 50% alcohol solution

If we have x liters of 50% alcohol, then we have 0.50*x liters of pure alcohol. This is added to 0.90*40 = 36 liters of pure alcohol (from the 90% solution).

So far we have 0.50*x + 36. This expression represents the total amount of pure alcohol. We want a 70% solution, so we want 70% of the total 40+x meaning 0.50*x + 36 is to be set equal to 0.70*(40+x) and we solve for x as shown below

0.50*x + 36 = 0.70*(40+x)

0.50*x + 36 = 0.70*(40)+0.70*(x)

0.50*x + 36 = 28+0.70*x

36 - 28 = 0.70*x - 0.50x

8 = 0.20x

0.20x = 8

x = 8/0.20

x = 40

So that is why the answer is choice A. 40 liters

6 0
2 years ago
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