Given:
Amount = Rs. 34476
Rate of compound interest = 4%
Time =
years
To find:
The principal value.
Solution:
Formula for amount is

Where, P is principal value, r is rate of interest and t is time in years.
Putting the given values, we get




Now,


Therefore, the value of sum or principal value is Rs.31256.
Hey,
We can see here 2 of the angles are equal and the third one is a right angle right?
That means it is an isosceles triangle since they have 2 equel angles and a right anlgle.
Another feature of the isosceles triangle is that 2 sides are equal.
We are given one side is 5.5 right?
So the side BC has to be 5.5 or the side AB has to be 5.5
In isosceles triangles the side opposite to the 90 degree angle is the hypotenuse.This means it is the longest angle.
So it has to be AB which is equal to 5.5 since BC is the hypotenuse.
Hope this helps,Happy New Year
Answer:
B: A square is a quadrilateral
Step-by-step explanation:
Answer:
R(16,-8)
Step-by-step explanation:
if (x1,y1) and (x2,y2) are coordinates of two points and (x,y) the coordinate of midpoint.
then x=(x1+x2)/2
and y=(y1+y2)/2
let coordinates of R are (x,y)
4=(-8+x)/2
8=-8+x
x=8+8=16
-3=(2+y)/2
-6=2+y
y=-6-2=-8
so R is (16,-8)
Answer:
See explanation
Step-by-step explanation:
1. Given the expression
![\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%20%7D)
Note that
![\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E5%7D%3Dx%5E%7B%5Cfrac%7B5%7D%7B7%7D%7D%20%5C%5C%20%5C%5C%5Csqrt%5B4%5D%7Bx%5E2%7D%3Dx%5E%7B%5Cfrac%7B2%7D%7B4%7D%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
When dividing
by
we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

and the result is ![x^{\frac{3}{14}}=\sqrt[14]{x^3}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B3%7D%7B14%7D%7D%3D%5Csqrt%5B14%5D%7Bx%5E3%7D)
2. Given equation ![3\sqrt[4]{(x-2)^3} -4=20](https://tex.z-dn.net/?f=3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20-4%3D20)
Add 4:
![3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24](https://tex.z-dn.net/?f=3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20-4%2B4%3D20%2B4%5C%5C%20%5C%5C3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%3D24)
Divide by 3:
![\sqrt[4]{(x-2)^3} =8](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20%3D8)
Rewrite the equation as:

Hence,
