What is the solution to this equation? 325 + 12 = 39
2 answers:
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Since the figure is a parallelogram, then SP=RQ, and SR=PQ.
To find SR, we draw right triangle SAR, as shown in the picture, where the coordinates of A are clearly (-3, -2).
Thus, we can see that SA=4 units, and AR=4 units. By the Pythagorean theorem,
Similarly, to find SP, which is equal to QR, we draw the triangle PBS, where the coordinates of B are (-2, 2).
Clearly, PB=3 and SB=1, thus using the Pythagorean theorem in right triangle PBS:
units.
The perimeter of the parallelogram is SP+RQ+SR+PQ=
.
Answer: second choice
To find SR, we draw right triangle SAR, as shown in the picture, where the coordinates of A are clearly (-3, -2).
Thus, we can see that SA=4 units, and AR=4 units. By the Pythagorean theorem,
Similarly, to find SP, which is equal to QR, we draw the triangle PBS, where the coordinates of B are (-2, 2).
Clearly, PB=3 and SB=1, thus using the Pythagorean theorem in right triangle PBS:
The perimeter of the parallelogram is SP+RQ+SR+PQ=
Answer: second choice
The measure of their corresponding angles is equal the vertices of a quadrilateral ABCD are A(4, 8), B(10, 10), C(10, 4), and D(4, 4) and the vertices of another quadrilateral EFCD are E(4, 0), F(10, -2), C(10, 4), and D(4, 4). This can be obtained by plotting the quadrilaterals on a graph paper and comparing the figures.
<h3>Which conclusion is true about the quadrilaterals?</h3>Given that,
vertices of quadrilateral ABCD are A(4, 8), B(10, 10), C(10, 4), and D(4, 4)
vertices of quadrilateral EFCD are E(4, 0), F(10, -2), C(10, 4), and D(4, 4)
(x,y) ; (x, y-8)
ABCD is reflected across the line y=4 to get the quadrilateral EFCD.
Reflection means the size and shape of the quadrilaterals is same ⇒quadrilateral ABCD and quadrilateral EFCD are congruent.
Thus corresponding parts of congruent triangles are equal, corresponding angles will be equal.
Hence the measure of their corresponding angles is equal the vertices of a quadrilateral ABCD are A(4, 8), B(10, 10), C(10, 4), and D(4, 4) and the vertices of another quadrilateral EFCD are E(4, 0), F(10, -2), C(10, 4), and D(4, 4).
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