The asymptotes of the open loop transfer are:
The open loop transfer function is given as:
f(s) = 100(s + 1)/((s + 10)(s + 100))
Set the numerator of the function to 0.
So, we have:
f(s) = 0/((s + 10)(s + 100))
Evaluate
f(s) = 0
This means that, the vertical asymptote is y = 0
Set the denominator of the function to 0.
(s + 10)(s + 100) 0
Split
s + 10 = 0 and s + 100 = 0
Solve for s
s = -10 and s = -100
This means that, the horizontal asymptotes are s = -10 and s = -100
See attachment for the graph of the asymptotes
Read more about asymptotes at:
#SPJ1
Answer:
a) no roots not in LHP
b) 2 roots not in LHP
c) 2 roots not in the LHP
d) 2 roots not in the LHP
e) 2 roots not in LHP
Explanation:
No roots not in the LHP
2 roots not in the LHP
There are roots in the RHP (not all coefficients are greater than 0).
2 roots not in the LHP
There are two sign changes in the first column of the Routh array.
2 roots not in the LHP
2 roots not in LHP
check:
⇒
Answer:
P = 0.490 kip
Explanation:
given data
allowable bearing stress = 2 ksi
allowable tensile stress = 18 ksi
diameter = 0.31 in
outer diameter = 0.75 in
inner diameter (hole) = 0.50 in
solution
we find here cross section area of shank that is express as
Area = ..................1
area =
area = 0.0754 in²
and
now we get here allowable load in bolt will be
...................2
P =
P = 18 × 10³ × 0.0754
P = 1357.2 = 1.357 kip
and
now find here area of washer is
Area = .......................3
put here value
Area =
area = 0.2454 in²
so now we get here allowable load of washer will be
.....................4
P = 2 × 10³ × 0.245
P = 490 = 0.490 kip