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Nata [24]
3 years ago
7

The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release

235.0 kJ of energy?
Chemistry
2 answers:
Lelu [443]3 years ago
8 0
1 mole of gold = 197g

12.550 kJ-------------- 197g Au
235.0 kJ--------------------x
x = 3,69g Au

answer: 3,69g Au
Oksanka [162]3 years ago
6 0

Answer;3.67061 kg of gold must be solidified to release 235 kJ of energy.

Explanation:

Molar heat of gold = 12.550 kJ/mol

1 mole of gold releases = 12.550 kJ/mol

Or we can rewrite it as ,1 kJ of energy is given by[\frac{1}{12.550} mol

Then 235 kJ of energy will be released by:

\frac{1}{12.550 kJ}\times 235 kJ=18.72 moles of gold

Mass of gold in 18.72 moles = 18.72 mole × 196.08 g/mol =3,670.61 g =3.67061 kg

1 kg = 1000 g

3.67061 kg of gold must be solidified to release 235 kJ of energy.

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