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3 years ago

Can someone help me plz

Mathematics

1 answer:

stiks02 [169]3 years ago

7 0

Answer:

this is just a guess but 81

Step-by-step explanation:

I hope it is right, but I just did quick math.

so it might also be 82 if you round up to the nearest number. (sorry if this is confusing)

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Find the value of x. need the answer today please. Thank you.

charle [14.2K]

Answer:

x =8.34654305

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adjacent / hypotenuse

cos 33 = 7/x

Switching places with the x and the 33

x = 7/ cos 33

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3 0

2 years ago

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A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at

valina [46]

Answer:

$P(Same)=\frac{61}{190}$

Step-by-step explanation:

Given

$Red = 5$

$White = 6$

$Black = 9$

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

$Total = 5 + 6 + 9$

$Total = 20$

This is calculated as:

$P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)$

So, we have:

$P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1} + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}$

Note that: 1 is subtracted because it is a probability without replacement

$P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1} + \frac{9}{20} * \frac{9- 1}{20- 1}$

$P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19} + \frac{9}{20} * \frac{8}{19}$

$P(Same)=\frac{20}{380} + \frac{30}{380} + \frac{72}{380}$

$P(Same)=\frac{20+30+72}{380}$

$P(Same)=\frac{122}{380}$

$P(Same)=\frac{61}{190}$

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3 years ago

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wolverine [178]

For domain 2x sqrt(2+x)>0
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3 years ago

Determine the equation of the line passing through the points (4,-1) and (-2,-4)

jenyasd209 [6]

Answer:

y = 1/2x - 3

Step-by-step explanation:

the slope:

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the equation:

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$y-(-1)=\frac{1}{2} (x-4)$

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$y=\frac{1}{2} x-2-1$

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3 years ago

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Dimas [21]

Answer:2 11/24

Step-by-step explanation:

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2 years ago

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Can someone help me plz ​

Can someone help me plz