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2 years ago

Given that tangent squared theta = three-eighths, what is the value of secant theta?

Mathematics

2 answers:

Nuetrik [128]2 years ago

7 0

Answer:

11/8

Step-by-step explanation:

docker41 [41]2 years ago

3 0

Answer:

B) Plus-or-minus StartRoot eleven-eighths EndFraction

${ \tan }^{2} \theta = \frac{3}{8} \\ but : { \tan }^{2} \theta = { \sec }^{2} \theta - 1 \\ \therefore { \sec}^{2} \theta - 1 = \frac{3}{8} \\ { \sec }^{2} \theta = \frac{11}{8} \\ \sec( \theta) = \sqrt{ \frac{11}{8} }$

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Help me PLease<br><br><br><br> also explain how to do it

Lady bird [3.3K]

❥ $\Large\pmb{ \underline {\tt Answer}}$

So we can only find x if other two angles of triangle is given.

In angle B as u can see boxed shape angle is there then it probably means it's a 90° angle.

We know sum of angles of triangle = 180°

{Reson :-

There's a formula to fund sum of angles of figure

(n-2) × 180
(3 -2) × 180
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}

Now Let's proceed

$\boxed{ \rm Side_1+Side_2+Side_3 = 180\degree}$

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$\dashrightarrow \tt 90 \degree + 55 \degree + c = 180 \degree$

$\\ \\$

$\dashrightarrow \tt 145\degree + c = 180 \degree$

$\\ \\$

$\dashrightarrow \tt c = 180 \degree - 145\degree$

$\\ \\$

$\dashrightarrow \tt c = 35\degree$

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