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2 years ago

Given that tangent squared theta = three-eighths, what is the value of secant theta?

Mathematics

2 answers:

Nuetrik [128]2 years ago

7 0

Answer:

11/8

Step-by-step explanation:

docker41 [41]2 years ago

3 0

Answer:

B) Plus-or-minus StartRoot eleven-eighths EndFraction

${ \tan }^{2} \theta = \frac{3}{8} \\ but : { \tan }^{2} \theta = { \sec }^{2} \theta - 1 \\ \therefore { \sec}^{2} \theta - 1 = \frac{3}{8} \\ { \sec }^{2} \theta = \frac{11}{8} \\ \sec( \theta) = \sqrt{ \frac{11}{8} }$

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Nellie has a bankruptcy on her credit report and therefore pays higher interest rates on her current loans. She took out a car l

neonofarm [45]

The amount of extra interest that will be paid is $24300

Since Nellie took out a car loan for $45,000 payable for 6 years at an interest rate of 15%, the interest that she will pay will be:

= ($45000 × 6 × 15) / 100

= $40500

On the other hand, if she hasn't applied for bankruptcy, the amount that she will pay will be:

= ($45000 × 6 × 6) / 100

= $16200

Therefore, the difference between the interest will be:

= $40500 - $16200

= $24300

The correct option is $24300. The given options are incorrect.

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2 years ago

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Need help ASAP please!!!!

kenny6666 [7]

Answer:

72 divided by 8 = t

Step-by-step explanation:

4 0

2 years ago

Landscape company sold 25 trees on Friday. There were a total of 125 trees in inventory. What percent of the trees were sold on

Arte-miy333 [17]

Answer: 20%

Step-by-step explanation:

First determine how many times 25 fits in 125. It’s 5 right. Now turn that into a percent. That leading to 20%

5 0

3 years ago

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Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

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3 years ago

How many time does 16 go into 4

Artemon [7]

4 can go into 16 4 times

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2 years ago

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