Question

Given that tangent squared theta = three-eighths, what is the value of secant theta?

Answer 1

Answer:

11/8

Step-by-step explanation:

Answer 2

Answer:

B) Plus-or-minus StartRoot eleven-eighths EndFraction

${ \tan }^{2} \theta = \frac{3}{8} \\ but : { \tan }^{2} \theta = { \sec }^{2} \theta - 1 \\ \therefore { \sec}^{2} \theta - 1 = \frac{3}{8} \\ { \sec }^{2} \theta = \frac{11}{8} \\ \sec( \theta) = \sqrt{ \frac{11}{8} }$