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liubo4ka [24]
3 years ago
7

HEEEELP PLEASE I NEED HELP DONT SAY "I DONT KNOW" PLEASE

Mathematics
2 answers:
BaLLatris [955]3 years ago
8 0

Answer:

B. 4 hours

Step-by-step explanation:

If the distance is total of 56 miles and he travels 14 miles per hour,

divide 56/14

56/14=4

4 hours to complete the 56-mile race

goblinko [34]3 years ago
6 0

Step-by-step explanation:

Time taken to complete the race

= Distance / Speed

= 56 miles / (14 miles/hr)

= 4 hours. (B)

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I need help getting the answer for the 1st question
Karo-lina-s [1.5K]
If we have two similar triangles:
Triangle 1 (base 1 , height1).
Triangle 2 (base 2, height 2)
Then:

base 1 /height 1=base 2 /height 2

Data:
base 1=0.2 m
height 1= 1 m
base 2= 8 m
height 2=x

We calculate the height of the tower:
base 1 /height 1=base 2 /height 2
0.2 m / 1m=8 m / x
x=(8 m * 1 m) / 0.2 m
x=8 m²/0.2 m
x=40 m

Answer. the heigth of the tower will 40 m

3 0
3 years ago
What is the area of this regular pentagon that has been divided into five congruent triangles?
Len [333]

Answer:

120 cm^2.

Step-by-step explanation:

The area of one triangle = 1/2 * base * height

= 1/2 * 8 * 6

= 1/2 * 48

= 24 cm^2

So area of the pentagon = 5 * 24

= 120 cm^2.

7 0
3 years ago
A has coordinates (1,1) and B has coordinates (4,3). if AB is a side of a square, what is the area of the square?
kvasek [131]
Area of the square:
A = s²
and s = AB = sqrt ( ( 4 - 1 )² + ( 3 - 1 )² )
s = √ ( 9 + 4 ) = √ 13
A = ( √13 )² = 13
Answer: Area of the square is 13 units².
8 0
3 years ago
The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

6=a(1+r)                    ...(ii)

Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

5 0
3 years ago
Solve by using elimination. Express your answer as an Ordered pair (-x +2y=3 3x-2y=7
MAVERICK [17]

Answer:

(5,4)

Step-by-step explanation:

-x+2y=3

3x-2y=7

Add the like terms( 2y and -2y)(-x and 3x)(3 and 7) together. Do this vertically. 2y and -2y cancel eachother out.

  • 2x=10

Divide both sides by 2

  • <u>x=5</u>

To find y, substitute x in for y in one of the equations

  • -5+2y=3

add 5 to both sides

  • 2y=8

Divide both sides by 2

  • <u>y=4</u>

Check:

  • -5+2(4)=3
  • 3=3
4 0
2 years ago
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