Answer:
The coordinates of point M' are
.
Step-by-step explanation:
According to the statement, we have the following translation rule:
(1)
Where:
- Original point.
- Translated point.
- Translation vector.
If we know that
, then the coordinates of the point M' are:


The coordinates of point M' are
.
Answer:
- (-6, 10)
- (-10, 9)
- (-11, -6)
- (-5, 1)
Step-by-step explanation:
<em>(x,y) → (x-8, y+4)</em>
1. (2, 6)
(2-8, 6+4)
<u>(-</u><u>6, 10)</u>
2. (-2, 5)
(-2-8, 5+4)
<u>(-10, 9)</u>
3. (-3, -10)
(-3-8, -10+4)
<u>(-11, -6)</u>
ídk man u should connect it to <u>(11, -7)</u> since it's the only choice closest to the right answer, but If u can write the correct then write this. there's prolly an error in that quiz ídk
4. (3, -3)
(3-8, -3+4)
<u>(-5, 1)</u>
<u> </u>still not in the choices nanii but <u>(5, -14)</u> is the only choice left and also the closest, and even if u use calculator the correct answer is still (-5, 1). sigh, I hope this helper at least
Yes i think it is reflection try reflection
Find the height of it with pythagoras
Root(100-36)=8
Volume = 1/3 pi r^2 h
1/3(36pi x 8)
=96pi
about 301.59ft^3
The domain and inverse of the function
is
Domain =
,

What is a function?
A function from A to B is a rule that assigns to each element of A a unique element of B. A is called the domain of the function and B is called the codomain of the function.
There are different operations on functions like addition, subtraction, multiplication, division and composition of functions.
The given function is

r(x) is not defined if x - 4 = 0
r(x) is not defined for x = 4
Domain =
,
Where
is the set of all real number
Let r(x) = y

<em />
To learn more about function, refer to the link:
brainly.com/question/22340031
#SPJ4