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oksano4ka [1.4K]
3 years ago
12

Help please it’s due soon just calculate the atomic mass of lithium that’s all i need

Chemistry
1 answer:
Zinaida [17]3 years ago
4 0
6.941u? Sorry if I get it wrong
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What is the volume or density
svetlana [45]

See the image below.

4 0
4 years ago
How many grams od Mg(OH)2 will be needed to neutralize 25 mlod
irina [24]

Answer:

0.0073 g

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For HCl :

Molarity = 0.010 M

Volume = 25 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 25×10⁻³ L

Thus, moles of HCl :

Moles=0.010 \times {25\times 10^{-3}}\ moles

Moles of HCl  = 0.00025 moles

Considering the reaction shown below as:-

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

2 moles of HCl reacts with 1 mole of Mg(OH)_2

So,

1 moles of HCl reacts with 1/2 mole of Mg(OH)_2

Also,

0.00025 moles of HCl reacts with \frac{1}{2}\times 0.00025 mole of Mg(OH)_2

Mole of Mg(OH)_2 = 0.000125 moles

Molar mass of Mg(OH)_2 = 58.3197 g/mol

Mass = Moles*Molar mass = 0.000125\times 58.3197\ g = 0.0073 g

5 0
3 years ago
Read 2 more answers
How many grams of lithium are in 6.02*10^21 atoms
valentinak56 [21]

the answer is 0.0693769. 6.02x10^21 x6.94/ 6.022x10^23 is the formua you would use.

7 0
4 years ago
A student increases the temperature of a 556 cm3 balloon from 278 K to 308 K. Assuming constant pressure, what should the new vo
Mandarinka [93]
The answer is:  [D]:  " 417 cm³ " .
_____________________________________________________
Explanation:  Use the formula:

V₁ /T₁= V₂ /T₂  ;

in which:  V₁ = initial volume = 556 cm³ ;
                T₁ = initial temperature = 278 K ;
                V₂ = final ("new") temperature = 308 K
                T₂ = final ("new:) volume = ?

Solve for  "V₂" ;

Since:  V₁ /T₁= V₂ /T₂ ;

We can rearrange this "equation/formula" to isolate "V₂" on one side of the equation; and then we can plug in our know values to solve for "V₂" ;
_______________________________________________________
       V₁ /T₁= V₂ /T₂  ;  Multiply EACH side of the equation by "T₂ " :

          →  T₂ (V₁ /T₁) = T₂  (V₂ /T₂) ;
______________________________
to get:

↔ T₂  (V₂ /T₂) = T₂ (V₁ /T₁) ;

     →  V₂ = T₂ (V₁ /T₁) ;
______________________________
Now, plug in our known values, to solve for "V₂" ;
______________________________
    →  V₂ = T₂ (V₁ /T₁) ;
______________________________
    →  V₂ = 308 K ( 556 cm³ /278 K)  ;
             → The units of "K" cancel to "1" ; and we have:
________________________________________________________
    →  V₂ = 308*( 556 cm³ / 278 ) = [(208 * 556) / 278 ] cm³ ;
Note:  We will keep the units of volume as:  "cm³ ";  since all the answer choices given are in units of:  "cm³ " ; {that is, "cubic centimeters"}.

   →  [(208 * 556) / 278 ] cm³ = [ (115,648) / (278) ] cm³ ;
                                        
              → For the "(115,648)" ;  round to "3 (three significant figures)" ;
                        → "(115,648)" → rounds to:  "116,000" ;
____________________________________________________
              →      (116,000) / (278) = 417.2661870503597122  ;
                                 → round to 3 significant figures; → "417 cm³ " ;
                                               → which corresponds with "choice [D]".
______________________________________________________
The answer is:  [D]:  "417 cm³ " .
______________________________________________________

3 0
3 years ago
Someone help me pls!
Naddika [18.5K]

Answer:Warm ocean currents originate near the equator and move towards the poles or higher latitudes while cold currents originate near the poles or higher latitudes and move towards the tropics or lower latitude.

Explanation:

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