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kap26 [50]
3 years ago
10

Be sure to answer all parts. Determine the electron-group arrangement, molecular shape, and ideal bond angle for the following m

olecule: SO3 Electron-group arrangement: V-shaped (bent) trigonal planar trigonal pyramidal seesaw Molecular shape: bent square pyramidal trigonal planar trigonal pyramidal Ideal bond angle: degrees
Chemistry
1 answer:
choli [55]3 years ago
7 0

Answer:

trigonal planar

Explanation:

The molecule SO3 is of the type AX3. The molecule is symmetrical and non polar.

There are three regions of electron density in the molecule. This corresponds to a trigonal planar geometry. This means that the three oxygen atoms are arranged at the corners of a triangle.  The bond angle is 120 degrees.

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Answer:

Percent yield of alum is 38.6%

Explanation:

Find attached calculations for detailed explanation.

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3 years ago
Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely wit
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Answer:

4 moles, 160 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For H_2SO_4:-  

Mass of H_2SO_4 = 196 g

Molar mass of H_2SO_4 = 98 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{196\ g}{98\ g/mol}

Moles\ of\ Sulfuric\ acid= 2\ mol

According to the given reaction:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,  

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

<u>Mass = Moles*molar mass = 4\times 40\ g = 160 g</u>

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3 years ago
Calculate the ratio of the velocity of helium atoms to the velocity of neon atoms at the same temperature.
o-na [289]

Answer:

vHe / vNe = 2.24

Explanation:

To obtain the velocity of an ideal gas you must use the formula:

v = √3RT / √M

Where R is gas constant (8.314 kgm²/s²molK); T is temperature and M is molar mass of the gas (4x10⁻³kg/mol for helium and 20,18x10⁻³ kg/mol for neon). Thus:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

The ratio is:

vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol

<em>vHe / vNe = 2.24</em>

<em />

I hope it helps!

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