You will need to know the volume and the concentration of the stock dilution in order to find the concentrations of the rest of the solutions you create.
Answer:
1) a. 2Fe(s) + 3Cl₂(g) → 2FeCl₃(s).
2) a. 0.4477 mol.
b. 0.4477 mol.
c. 72.61 g.
Explanation:
1) Consider the following reaction: iron (s) + chlorine (g) à iron (III) chloride
<em>a. Write the balanced chemical equation.</em>
- The balanced equation should apply the law of conversation of mass that the no. of different atoms is equal in both sides of the reaction (reactants and products sides).
So, the balanced chemical equation is:
<em>2Fe(s) + 3Cl₂(g) → 2FeCl₃(s).</em>
It is clear that 2 mol of Fe(s) react with 3 mol of Cl₂(g) to produce 2 mol of FeCl₃(s).
<em>2) 25.0 g of iron reacts with excess chlorine gas. </em>
<em>a. Calculate the moles of iron reactant.</em>
- The no. of moles of Fe (n) can be calculated using the relation:
<em>n = mass/molar mass =</em> (25.0 g)/(55.845 g/mol) = <em>0.4477 mol.</em>
<em>b. Calculate the moles of iron (III) chloride.</em>
<em><u>Using cross multiplication:</u></em>
2 mol of Fe produce → 2 mol of FeCl₃, from stichiometry.
∴ 0.4477 mol of Fe produce → 0.4477 mol of FeCl₃.
∴ The no. of moles of iron (III) chloride produced is 0.4477 mol.
<em>c. Calculate the mass of iron (III) chloride.</em>
- We can calculate the mass of iron (III) chloride produced using the relation:
mass of iron (III) chloride = (no. of moles)*(molar mass) = (0.4477 mol)*(162.2 g/mol) = 72.61 g.
Answer:
(C) 2
Explanation:
Methanol is an organic compound which burns with oxygen to produce carbon dioxide and water.
Multiply coefficients times subscripts for each element in the formula, We get that there are 2 number of atoms of the carbon, 8 number of atoms of the hydrogen, and 8 number of atoms of the oxygen on both sides of equation. Hence, it is balanced.
<u>The coefficient of methanol from the balanced reaction is 2.</u>
I think 5.50 M x 35.0 mL x molar mass of RbOH = mass (g)
