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Juliette [100K]
2 years ago
11

Use the following to calculate ΔH°latice of MgF₂:

Chemistry
1 answer:
mash [69]2 years ago
7 0

Yes, Since magnesium ions have a charge that is two times greater than that of lithium and sodium ions, MgF2 has higher lattice energy than LiF and NaCl.

Lattice energy: MgF2 (s) → Mg2+(g) + 2 F–(g)

Use Hess’s law:                                      

∆Hº Mg(s) → Mg(g)                                  

Mg(s) → Mg(g) ΔH° = 148kJ F₂(g) → 2F(g) ΔH° = 159kJ

M(g) → Mg⁺ (g) + e⁻ ΔH° = 738kJ

M⁺(g) → Mg²⁺ (g) + e⁻ ΔH° = 1450kJ

F(g) + e⁻ → F⁻(g) ΔH° = -328kJ

Mg(s) + F₂(g) → MgF₂(s) ΔH° = -1123KJ

(Reaction is reversed and the sign of ∆Hº changed.)  

MgF2 (s) → Mg2+(g) + 2F–(g)            

2962 kJ

As ion charge rises, lattice energy rises as well. The lattice energy increases as the ion charge variable is increased. Accordingly, ions with higher charge intensities will result in ionic compounds with higher lattice energies.

Learn more about lattice energy here:

brainly.com/question/18222315

#SPJ4

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2. Increase B

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3. Increase C

On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.

4. Decease A

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5. Decease B

On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.

6. Decease C

On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.

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On doubling A and halving B, equilibrium constant of the reaction = K'

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The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.

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On doubling B and C, equilibrium constant of the reaction = K'

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The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.

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