Question

How many grams are there in 3.26 x 10^25 Molecules of Mg(NO3)2?

Answer 1

Answer:

8025.996 grams are there in 3.26*10²⁵ Molecules of Mg(NO₃)₂.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ molecules are contained in 1 mole of the compound, 3.26*10²⁵ molecules are contained in how many moles of the compound?

$amount of moles=\frac{3.26*10^{25}molecules*1 mole }{6.023*10^{23}molecules }$

amount of moles= 54.12

Molar mass is the mass of one mole of a substance, which can be an element or a compound. Being the molar mass of the compound Mg(NO₃)₂ 148.3 g/mole, so 54.12 moles of the compound contains 8025.996 grams.

8025.996 grams are there in 3.26*10²⁵ Molecules of Mg(NO₃)₂.