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stepan [7]
4 years ago
9

Emil bought a camera for $268.26, including tax. He made a down payment of $12.00 and paid the balance in 6 equal monthly paymen

ts. What was Emil's monthly payment for this camera?
Mathematics
1 answer:
AVprozaik [17]4 years ago
8 0
Firstly, subtract the cost that Emil has already put down;
268.26-12= 256.26
Then divide by the monthly installments
256.26/ 6= 42.71
Therefore, Emil pays $42.71 per month 
Hope this helps :) <span />
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What is the expected probability of obtaining a head when flipping a coin? What is the expected probability
Illusion [34]
50/50

With a two-sided coin, the probability of it landing on heads or tails will always be 50.
6 0
3 years ago
(4x+5) (3x+1) -3 (x+1)<br>​
ollegr [7]

Answer:

-36x^3 - 69x^2 - 34x - 5

Step-by-step explanation:

(4x + 5) (3x + 1) -3 (x + 1)

(4x + 5) (3x + 1) ( -3x - 1)

12x^2 + 4x + 15x +5

Combine like terms

12x^2 + 19x + 5 (-3x - 1)

-36x^3 -57x^2 - 15x^2 -5

Combine like terms

-36x^3 - 69x^2 - 34x - 5

4 0
2 years ago
Four more than 3 times a number t written asfour
Orlov [11]
Four more than 3 times a number t

3t+4

If you are telling me to write the variable t as 4- then:

3(4)+4

12+4

16

Hope this helps!
~cupcake
5 0
4 years ago
Read 2 more answers
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
Alla and balla together drink 750ML of water. Of alla drinks 50% more than balla how much does Alla drink
Akimi4 [234]

Answer:

450 ml.

Step-by-step explanation:

Let x be the amount of water drank by Alla and y be the amount of water drank by Balla.

We have been given that Alla and Balla together drink 750 ML of water. We can represent this information as:

x+y=750...(1)  

We are also told that Alla drinks 50% more than Balla. We can represent this information as:

x=1.5y...(2)

From equation (1) we will get,

y=750-x  

Upon substituting this value in equation (2) we will get,

x=1.5(750-x)

Upon distributing 1.5 to right hand side of the equation we will get,

x=1125-1.5x

Upon adding 1.5x to both sides of equation we will get,

x+1.5x=1125-1.5x+1.5x

2.5x=1125

Let us divide both sides of our equation by 2.5.

\frac{2.5x}{2.5}=\frac{1125}{2.5}

x=450

Therefore, Alla drank 450 ml of water.

8 0
3 years ago
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