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motikmotik
3 years ago
8

IF YOU COULD ANSWER + PROVIDE HOW YOU GOT THE ANSWER FOR ANY OF THESE THAT WOULD BE GREAT!

Chemistry
1 answer:
Akimi4 [234]3 years ago
8 0

Answer:

I could do all the questions and explain profusely in under 1hr for cheap price. email me at lyndertutors (at) gm,ail.com for negotiations.

Explanation:

check my profile... I help students in their assignments.

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How many liters are in 3.45 moles of oxygen gas at STP?
just olya [345]

Answer:

22.4L of one mole of any gas

or you can use PV=nRT

3.45*22.4=77.28

Explanation:

5 0
3 years ago
What determines how fast a substance will dissolve
Blababa [14]

Answer:

(1) the surface area of the solute,

(2) the temperature of the solvent,

(3) the amount of agitation that occurs when the solute and the solvent are mixed.

Explanation:

8 0
4 years ago
Read 2 more answers
Complete the nuclear equation<br><br> 42 K → 0 e <br>19____-1
kenny6666 [7]

Answer:

42 19 K→42 20 Ca+e−

Explanation:

Naturally-occurring potassium atoms have a weighted average atomic mass of 39.10 (as seen on most modern versions of the periodic table.) Each potassium atom contains 19 protons p+ and thus an average potassium atom contains about 39.10−19≈20 neutrons n0.

This particular isotope of potassium-42 contains 42 nucleons (i.e., protons and neutrons, combined;) Like other isotopes of potassium 19 out of these nucleons are protons; the rest 42−19=23 are therefore neutrons.

5 0
3 years ago
The density of an element is 19.3 g/cm^3. What is its density in kg/m^3?
Karolina [17]
First, you need to know 1 kg = 10^3 g. And 1 m^3 = 10^6 m^3. So the 1 g/cm3 = 10^3 kg/m3. So the answer is 1.93*10^4 kg/m3.
5 0
4 years ago
0.785 moles of N2,fill a balloon at 1.5 atm and 301 K.<br> What is the volume of the balloon?
Tcecarenko [31]

Answer:

V = 12.93 L

Explanation:

Given data:

Number of moles = 0.785 mol

Pressure of balloon = 1.5 atm

Temperature = 301 K

Volume of balloon = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values.

V = nRT/P

V = 0.785 mol × 0.0821 atm.L/ mol.K × 301 K / 1.5 atm

V = 19.4 L /1.5

V = 12.93 L

7 0
3 years ago
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