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3 years ago

How do I solve 9.85xs;s=4

Mathematics

1 answer:

maria [59]3 years ago

7 0

Answer:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "9.85" was replaced by "(985/100)".

Bad syntax in Linear Equations

... V

(985/100)xs;s=4

Bad syntax in Linear Equations

........... V

(985/100)xs;s=4

Multiplication of variables in Linear Equations

........... V

985/100xs;s=4

Equation without an equal sign

............ V

985/100xs;s=4

Step-by-step explanation:

BRAINLIST PLEASE

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Help please ASAP !! !!!!

goblinko [34]

Answer:

im gonna say 23 or 24 not 100% sure

Step-by-step explanation:

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3 years ago

In the figure above, what is the area of triangle QRS?

Vlad [161]

Answer:

D) 20.

Step-by-step explanation:

First find the value of x using Pythagoras theorem:

10^2 = x^2 + (2x)^2

5x^2 = 100

x^2 = 20

x = √20

= 2√5.

So the area of triangle

= 1/2 * base * height

= 1/2 * 2x * x

= x^2

= (2√5)^2

= 20.

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2 years ago

I need clause to this : 64-(13-7)

katen-ka-za [31]

64 - (13 - 7) = 64 - 6 = 58

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3 years ago

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Illusion [34]

Answer:

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3 years ago

When a scientist conducted a genetics experiments with peas, one sample of offspring consisted of 943 peas, with 717 of them hav

pshichka [43]

Using the normal approximation to the binomial distribution, it is found that:

a) 0.242 = 24.2% probability of getting 717 or more peas with red flowers.

b) Since Z < 2, 717 peas with red flowers is not significantly high.

c) Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

For each pea, there are only two possible outcomes. Either they have a red flower, or they do not. The probability of a pea having a red flower is independent of any other pea, which means that the binomial distribution is used to solve this question.

Binomial distribution:

Probability of x successes on n trials, with p probability.

Normal distribution:

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

If Z > 2, the result is considered significantly high.

If $np \geq 10$ and $n(1-p) \geq 10$ , the binomial distribution can be approximated to the normal with:

$\mu = np$

$\sigma = \sqrt{np(1-p)}$

In this problem:

943 peas, thus, $n = 943$
3/4 probability of being red, thus $p = \frac{3}{4} = 0.75$ .

Applying the approximation:

$\mu = np = 943(0.75) = 707.25$

$\sigma = \sqrt{np(1-p)} = \sqrt{943(0.75)(0.25)} = 13.297$

Item a:

Using continuity correction, this probability is $P(X \geq 717 - 0.5) = P(X \geq 716.5)$ , which is 1 subtracted by the p-value of Z when X = 716.5.

Then:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{716.5 - 707.25}{13.297}$

$Z = 0.7$

$Z = 0.7$ has a p-value of 0.758.

1 - 0.758 = 0.242

0.242 = 24.2% probability of getting 717 or more peas with red flowers.

Item b:

Since Z < 2, 717 peas with red flowers is not significantly high.

Item c:

Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

A similar problem is given at brainly.com/question/25212369

6 0

3 years ago