All categories

2 years ago

How do I solve 9.85xs;s=4

Mathematics

1 answer:

maria [59]2 years ago

7 0

Answer:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "9.85" was replaced by "(985/100)".

Bad syntax in Linear Equations

... V

(985/100)xs;s=4

Bad syntax in Linear Equations

........... V

(985/100)xs;s=4

Multiplication of variables in Linear Equations

........... V

985/100xs;s=4

Equation without an equal sign

............ V

985/100xs;s=4

Step-by-step explanation:

BRAINLIST PLEASE

You might be interested in

(08.01)Which of the following statements shows a characteristic of a statistical question?

jonny [76]

It is not A,B, or D.

so it has to be C. wish I knew this when taking test.

let me know if it was right. I hope this is somewhat helpful.

4 0

2 years ago

Read 2 more answers

The Japanese 5 yen coin has a hole in the middle. What are the possible ways to calculate the difference between the distances f

ipn [44]

Answer:a) Subtract the two diameters and multiply by 3.14

d) Subtract the circumference of the hole from the circumference of the coin

Step-by-step explanation:

i just did the assignment

9 0

2 years ago

Read 2 more answers

16 inches to centimeters

asambeis [7]

Answer:

In centimeters, it would be 40.64 centimeters.

7 0

2 years ago

Read 2 more answers

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

The probability that both televisions work is: 0.42

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

3 years ago

walker is reading a book that is 792 pages. He reads 15 pages a day during the week, and 25 pages a day during the weekend. Afte

Gnesinka [82]

Answer: The total number of pages does Walker still have left to read before he finishes the book is 167 and this can be determined by using the arithmetic operations.

Step-by-step explanation: edge 2021!

5 0

1 year ago

Read 2 more answers