Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
2+n/5
Step-by-step explanation:
sum=plus
quotient=divide
number=n
<span>1. </span><span>Your total cost if 11.50 dollars.
It says that you ordered pancakes and a fruit cup
Pancake costs = x
Fruit cup cost = 1.50 dollars
you leave a tip = 15%
The equation would be:
=> (1.50 + x) .15 = 11.50 dollars
=> x = 11.50 – 1.50 x .15
=> Now, let’s find the cost of the
pancake
=> 11.50 - 1.50 fruit cake = 10
=> 10 x .15 tip = 8.5
Thus, the price of the pancake is 8.5</span>
