If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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By the way I looked this up but heres the best ive got
<span>Simplifying
(-1x + 27) + (16x + 4) = 0
Reorder the terms:
(27 + -1x) + (16x + 4) = 0
Remove parenthesis around (27 + -1x)
27 + -1x + (16x + 4) = 0
Reorder the terms:
27 + -1x + (4 + 16x) = 0
Remove parenthesis around (4 + 16x)
27 + -1x + 4 + 16x = 0
Reorder the terms:
27 + 4 + -1x + 16x = 0
Combine like terms: 27 + 4 = 31
31 + -1x + 16x = 0
Combine like terms: -1x + 16x = 15x
31 + 15x = 0
Solving
31 + 15x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-31' to each side of the equation.
31 + -31 + 15x = 0 + -31
Combine like terms: 31 + -31 = 0
0 + 15x = 0 + -31
15x = 0 + -31
Combine like terms: 0 + -31 = -31
15x = -31
Divide each side by '15'.
x = -2.066666667
Simplifying
x = -2.066666667</span>
tim is 13.
let tim's age be t and sam s.
the statement implies 2t + 9 = s.
solving,
2t + 9=35;
2t = 35-9;
2t =26; hence t is 13
3x + 6 - 2X + 7. 3X -2X +6+7. X + 13
