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lakkis [162]
3 years ago
10

891 is 99% of what amount?

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
900! Have a great day! :D
vaieri [72.5K]3 years ago
6 0

Answer:

900

Step-by-step explanation:

Hope this helps!

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Number of Tickets Total Cost 1 $2.50 2 ? 3 $7.50 4 ? 5 $12.50 6 $15.00 7 $17.50 Assuming that the cost of tickets follows the sa
Gala2k [10]
2= 5.50 4= 10.50 here is your answer 
7 0
3 years ago
Barbara, Mark, and Carlos participated in the third heat of “The Big Race”. Barbara thought she could win with a 3 meter head st
steposvetlana [31]
Distance to travel = 20 m.
Let us determine the time, t, that each participant took to complete 20 m.

Barbara:
Average speed = (3 m)/(2 s) = 1.5 m/s
t = 20/1.5 = 13.3 s

Mark:
t =  5 s

Carlos:
y = x + 1
where
y = 20 m
x = time, t
Therefore
t =x = y - 1 = 20 - 1 = 19 s

Summary:
Barbara:  13.3 s
Mark:       5 s
Carlos:     19 s

Answer:
The winner is Mark
7 0
3 years ago
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

8 0
3 years ago
Read 2 more answers
Alice tyre pressure gauge shows a reading which is 8% lower than actual pressure
olasank [31]

Answer:

30.8936

Step-by-step explanation:

Pressure guage reading is 8% lower than tbe actual pressure.

Therefore, for a tyre with guage pressure, 33.58 ;

The actual pressure of tyre would be :

Guage pressure - 8% of guage pressure

33.58 - (0.08 * 33.58)

33.58 - 2.6864

= 30.8936

Actual pressure = 30.8936

3 0
3 years ago
If 96 students are going on a field trip 12 chaperones are needed how many chaperones are needed we f 125 students are going on
Musya8 [376]

Answer:

4500

Step-by-step explanation:

7 0
3 years ago
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