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likoan [24]
1 year ago
5

5 g of gold and 25 g of silver are mixed to form a single-phase ideal solid solution. (a) how many moles of solution are there?

(b) what are the mole fractions of gold and silver?
Chemistry
1 answer:
worty [1.4K]1 year ago
3 0

Mole fraction for silver= 0.2317643/0.3079193

                                     = 0.7526787

Mole fraction for gold=0.076155/0.3079193

                                    =0.2473212

What is Molar Fraction?

The mole fraction is the product of the number of molecules of a specific component in a mixture and its total molecular weight. It serves as a means of indicating how concentrated a solution is.

It is a unit of concentration, defined as the product of the moles of a component and the moles of the entire solution. When all the parts of a solution are summed up, their mole fraction equals 1.

molar mass of silver = 107.8682g/mol

Molar mass of gold= 196.96657g/mol

Therefore mole = mass/molar mass

For silver: 25g/107.8682g/mol = 0.2317643mol

For gold: 15g/196.96657g/mol= 0.076155mol

Total number of mole= 0.2317643+0.076155

                                    = 0.30791193mol

Mole fraction for silver= 0.2317643/0.3079193

                                      = 0.7526787

Mole fraction for gold=0.076155/0.3079193

                                     =0.2473212

Learn more about Mole Fraction from given link

brainly.com/question/28590918

#SPJ4

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Explanation:

Hello there!

In this case, by bearing to to mind the given conditions, it is firstly possible to determine the initial volume of the closed system via the ideal gas equation:

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