Question

5 g of gold and 25 g of silver are mixed to form a single-phase ideal solid solution. (a) how many moles of solution are there? (b) what are the mole fractions of gold and silver?

Answer 1

Mole fraction for silver= 0.2317643/0.3079193

                                     = 0.7526787

Mole fraction for gold=0.076155/0.3079193

                                    =0.2473212

What is Molar Fraction?

The mole fraction is the product of the number of molecules of a specific component in a mixture and its total molecular weight. It serves as a means of indicating how concentrated a solution is.

It is a unit of concentration, defined as the product of the moles of a component and the moles of the entire solution. When all the parts of a solution are summed up, their mole fraction equals 1.

molar mass of silver = 107.8682g/mol

Molar mass of gold= 196.96657g/mol

Therefore mole = mass/molar mass

For silver: 25g/107.8682g/mol = 0.2317643mol

For gold: 15g/196.96657g/mol= 0.076155mol

Total number of mole= 0.2317643+0.076155

                                    = 0.30791193mol

Mole fraction for silver= 0.2317643/0.3079193

                                      = 0.7526787

Mole fraction for gold=0.076155/0.3079193

                                     =0.2473212

Learn more about Mole Fraction from given link

brainly.com/question/28590918

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