Answer:
- Volume = <u>2.0 liter</u> of 1.5 M solution of KOH
Explanation:
<u>1) Data:</u>
a) Solution: KOH
b) M = 1.5 M
c) n = 3.0 mol
d) V = ?
<u>2) Formula:</u>
Molarity is a unit of concentration, defined as number of moles of solute per liter of solution:
<u>3) Calculations:</u>
- Solve for n: M = n / V ⇒ V = n / M
- Substitute values: V = 3.0 mol / 1.5 M = 2.0 liter
You must use 2 significant figures in your answer: <u>2.0 liter.</u>
The answer to this question will be C
First, we will get the average pH of the two given values:
average pH = (6.4+8) / (2) = 7.2
At this average pH, the concentration of the acid from the phenol red is equal to the concentration of the base.
pH = 7.2
[H+] = 10^(-7.2) = 6.3 * 10^-8
Phenol red has the general formula HA, this gives us:
HA <.......> H+ + A-
At pH = 7.2, [H+] = [A-]
<span>Ka = [H+][A-]/ [HA]
</span>Ka = [H+] = <span>6.3 x 10^-8</span>
Answer:
![^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e](https://tex.z-dn.net/?f=%5E%7B32%7D_%7B14%7DSi%5Crightarrow%20%5E%7B32%7D_%7B15%7DP%2Be%5E-%2B%5Cbar%7Bv%7D_e)
Explanation:
Beta decay conserves the lepton number. In
decay, the atomic number of the element increases which is accompanied by the release of an electron antineutrino,
.
For example:-
![^A_ZX\rightarrow ^A_{Z+1}X+e^-+\bar{v}_e](https://tex.z-dn.net/?f=%5EA_ZX%5Crightarrow%20%5EA_%7BZ%2B1%7DX%2Be%5E-%2B%5Cbar%7Bv%7D_e)
The
decay of silicon-32 is shown below as:-
![^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e](https://tex.z-dn.net/?f=%5E%7B32%7D_%7B14%7DSi%5Crightarrow%20%5E%7B32%7D_%7B15%7DP%2Be%5E-%2B%5Cbar%7Bv%7D_e)
ionic bond:
Bond formed when an atom donates its electron and other atom receives those electrons.
polar covalent:
Bond formed by equal sharing of electrons between both the atoms and there is an electronegativity difference between the two atoms.
Nonpolar covalent:
Bond formed by equal sharing of electrons between both the atoms and there is no electronegativity difference between the two atoms.
Metallic:
Formed between two metals.
So the bond between :
Phosphorus and chlorine-polar covalent bond as it is formed by equal sharing of electrons between both the atoms and there is an electronegativity difference between the two atoms.
Potassium and oxygen -ionic bond as here potassium donates its electron and oxygen receives those electrons
Fluorine and fluorine -Non polar covalent bond as formed by equal sharing of electrons between both the atoms and there is no electronegativity difference between the two atoms.
Copper and aluminum-metallic bond as Formed between two metals.
Carbon and fluorine -polar covalent bond as it is formed by equal sharing of electrons between both the atoms and there is an electronegativity difference between the two atoms.
Carbon and hydrogen --Non polar covalent bond as formed by equal sharing of electrons between both the atoms and there is no electronegativity difference between the two atoms.
Aluminum and oxygen--ionic bond as here aluminum donates its electron and oxygen receives those electrons
Silver and copper --metallic bond as Formed between two metals.