let's firstly convert both fractions with the same denominator, by simply <u>multiplying each fraction by the other's denominator</u>, let's proceed.
![\bf -\cfrac{3}{4}\cdot \cfrac{3}{3}\implies \boxed{-\cfrac{9}{12}}~\hfill -\cfrac{1}{3}\cdot \cfrac{4}{4}\implies \boxed{-\cfrac{4}{12}} \\\\[-0.35em] ~\dotfill\\\\ \boxed{-\cfrac{9}{12}}~~,~~\stackrel{-\frac{2}{3}}{-\cfrac{8}{12}}~~,~~-\cfrac{7}{12}~~,~~\stackrel{-\frac{1}{2}}{-\cfrac{6}{12}}~~,~~-\cfrac{5}{12}~~,~~\boxed{-\cfrac{4}{12}}](https://tex.z-dn.net/?f=%5Cbf%20-%5Ccfrac%7B3%7D%7B4%7D%5Ccdot%20%5Ccfrac%7B3%7D%7B3%7D%5Cimplies%20%5Cboxed%7B-%5Ccfrac%7B9%7D%7B12%7D%7D~%5Chfill%20-%5Ccfrac%7B1%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B4%7D%5Cimplies%20%5Cboxed%7B-%5Ccfrac%7B4%7D%7B12%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cboxed%7B-%5Ccfrac%7B9%7D%7B12%7D%7D~~%2C~~%5Cstackrel%7B-%5Cfrac%7B2%7D%7B3%7D%7D%7B-%5Ccfrac%7B8%7D%7B12%7D%7D~~%2C~~-%5Ccfrac%7B7%7D%7B12%7D~~%2C~~%5Cstackrel%7B-%5Cfrac%7B1%7D%7B2%7D%7D%7B-%5Ccfrac%7B6%7D%7B12%7D%7D~~%2C~~-%5Ccfrac%7B5%7D%7B12%7D~~%2C~~%5Cboxed%7B-%5Ccfrac%7B4%7D%7B12%7D%7D)
Answer: 216
Step-by-step explanation:
The LCM of 24 and 54 is 216. To find the least common multiple of 24 and 54, we need to find the multiples of 24 and 54 (multiples of 24 = 24, 48, 72, 96 . . . . 216; multiples of 54 = 54, 108, 162, 216) and choose the smallest multiple that is exactly divisible by 24 and 54, i.e., 216.
The answer is 4, 320, 000
explanation: the problem is asking what the population of city c is, and to do that you need to multiply city b times 2. therefore you do not need the population of city a, it is just there to confuse you
D.
first, eliminate B and C, because the highest degree in these two equation is 3, a 3-degree equation has 3 roots, not 4.
between A and D, A has the roots 0, 0, 7, and -7, all real roots.
D can be factored into (x²-49)(x²+1)=0
x²=49 or x²=-1
x=7 or -7, x=i or -i two real roots, two unreal roots
for the second equation:
first, find the first term by using the formula:
the nth term=the first term + (n-1)*difference
you are given the 13th term and d=3.7
a13=a1+(13-1)d
1.9=a1+12*3.7
a1=-42.5
the sum of the first 13 terms is S=(a1+a13)*(13/2)=(-42.5+1.9)*6.5=-263.9
Answer:
60 the volume 60
Step-by-step explanation:
i think I might be wrong
