Answer:
C)
<h3>
log(117.50 / (117.50 - 2050(0.012) ) / log(1+0.012 ) </h3>
Step-by-step explanation:
Formula to calculate compounded monthly payments
A = R( (1-(1+r)^-n) / r)
where
r = 0.14/12
= 0.012
A = 2050
R = 117.50
n =no. of payments
2050 = 117.50 (1 - (1 + 0.012)^-n / 0.012)
cross multiplication
2050 (0.012) / 117.50 = 1 - (1 + 0.012)^-n
1 on other side
(2050 (0.012) / 117.50) - 1 = - (1+0.012)^-n
eliminating minus sign
1 - (2050 (0.012) / 117.50) = (1+0.012)^-n
LCM
(117.50 - 2050(0.012) ) / 117.50 = (1 + 0.012)^-n
power in negative
(117.50 - 2050(0.012) ) / 117.50 = 1 / (1+0.012)^n
reciprocal
117.50 / (117.50 - 2050(0.012) ) = (1+0.012)^n
taking log
log(117.50 / (117.50 - 2050(0.012) ) = log(1+0.012)^n
Answer
log(117.50 / (117.50 - 2050(0.012) ) = n log(1+0.0120)
<h3>
log(117.50 / (117.50 - 2050(0.012) ) / log(1+0.012 ) = n</h3>
Answer:
Objective 3: Solve work problems Q25 Solve a work problem Homework. Unanswered Jennifer can sew 120 masks in 20 hr and Janice can sew 120 masks in 30 hr. How many hours does it take them to sew 120 masks if they work together?
Step-by-step explanation:
i think u should've put it in that format
We conclude that she needs to route 10 phone calls to spend a total of 20 minutes in the phone (assuming that the unit rate does not change).
<h3>
How many phone calls does Aaliyah have to route to spend a total of 20 minutes on the phone?</h3>
First, we know that she spends 10 minutes on the phone while routing 5 phone calls.
Then the unit rate is:
(5 phone calls)/(10 min) = 0.5 phone calls per min.
Now, if she spends 20 minutes, the number of phone calls that she will route (assuming that the unit rate does not change) is:
N = (0.5 phone calls per min)*20 min = 10 phone calls.
We conclude that she needs to route 10 phone calls to spend a total of 20 minutes in the phone (assuming that the unit rate does not change).
If you want to learn more about unit rates:
brainly.com/question/19493296
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Answer:
407.7
Step-by-step explanation:
volume = (4/3) * π * r³
(4/3)*PI*4.6^3=407.7
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Answer:
The 95% confidence interval for the mean savings is ($60.54, $81.46).
Step-by-step explanation:
As there is no information about the population standard deviation of savings and the sample is not large, i.e. <em>n</em> = 20 < 30, we will use a <em>t</em>-confidence interval.
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
For the data provided compute the sample mean and standard deviation as follows:
The critical value of <em>t</em> for <em>α</em> = 0.05 and (n - 1) = 19 degrees of freedom is:
*Use a <em>t</em>-table for the value.
Compute the 95% confidence interval for the mean savings as follows:
Thus, the 95% confidence interval for the mean savings is ($60.54, $81.46).