The pH of the buffer is 6.1236.
Explanation:
The strength of any acid solution can be obtained by determining their pH. Even the buffer solution strength of the weak acid can be determined using pH. As the dissociation constant is given, we can determine the pKa value as the negative log of dissociation constant value.
![pKa=-log[H] = - log [ 5.66 * 10^{-7}]\\ \\pka = 7 - log (5.66)=7-0.753=6.247\\\\pka = 6.247](https://tex.z-dn.net/?f=pKa%3D-log%5BH%5D%20%3D%20-%20log%20%5B%205.66%20%2A%2010%5E%7B-7%7D%5D%5C%5C%20%5C%5Cpka%20%3D%207%20-%20log%20%285.66%29%3D7-0.753%3D6.247%5C%5C%5C%5Cpka%20%3D%206.247)
The pH of the buffer can be known as
![pH = pK_{a} + log[\frac{[A-]}{[HA]}}]](https://tex.z-dn.net/?f=pH%20%3D%20pK_%7Ba%7D%20%2B%20log%5B%5Cfrac%7B%5BA-%5D%7D%7B%5BHA%5D%7D%7D%5D)
The concentration of ![[A^{-}] = Moles of [A]/Total volume = 0.608/2 = 0.304 M\\](https://tex.z-dn.net/?f=%5BA%5E%7B-%7D%5D%20%3D%20Moles%20of%20%5BA%5D%2FTotal%20volume%20%3D%200.608%2F2%20%3D%200.304%20M%5C%5C)
Similarly, the concentration of [HA] = ![\frac{Moles of HA}{Total volume} = \frac{0.809}{2} = 0.404](https://tex.z-dn.net/?f=%5Cfrac%7BMoles%20of%20HA%7D%7BTotal%20volume%7D%20%3D%20%5Cfrac%7B0.809%7D%7B2%7D%20%3D%200.404)
Then the pH of the buffer will be
pH = 6.247 + log [ 0.304/0.404]
![pH = 6.247 + log 0.304 - log 0.404=6.247-0.517+0.3936=6.1236](https://tex.z-dn.net/?f=pH%20%3D%206.247%20%2B%20log%200.304%20-%20log%200.404%3D6.247-0.517%2B0.3936%3D6.1236)
So, the pH of the buffer is 6.1236.
Answer:
Particles in a solid object are super tight and close to eachother. They do not move past eachother because it is a solid, not a liquid or gas.
Explanation:
Answer:
1.26x10^25 atoms of hydrogen
Explanation:
because there are 12 atoms of hydrogen in a molecule of glucose, multiply 12 by Avogadro's number (6.02x10^23) to get how many molecules of hydrogen there are in a mole of glucose. Then multiply that number by 1.75, which is the number of moles of glucose there is in this problem.
Is to find the problem to the investigation