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bogdanovich [222]
3 years ago
10

Tell whether the lines through the given points are parallel, perpendicular, or neither.

Mathematics
1 answer:
antoniya [11.8K]3 years ago
5 0

Answer:

The Slope of Line 1 is ->  -\frac{2}{9}

The Slope of Line 2 is -> -\frac{9}{2}

These two lines are - >  Perpendicular

Step-by-step explanation:

To find the slope of line one, you follow these steps:

First Coordinate 10 -> x1, 5 -> y1

Second Coordinate -8 -> x2, 9 -> y2

Then insert the assigned values into this equation:  \frac{y2-y1}{x2-x1} -> \frac{9-5}{-8-10} which equals \frac{4}{-18} which simplifies to -\frac{2}{9}

Then do the same process to find the slop of line 2:

First Coord: 2 -> x1, -4 -> y1

Second Coord: 11 -> x2, -6 -> y2

Then insert the values into this equation: \frac{y2-y1}{x2-x1}  ->\frac{11-2}{-6-(-4)} which equals \frac{9}{-2}.

We know the lines are perpendicular by:

a. Typing the equations of the lines into a graphing calculator and observing the graph

b. Looking at the slopes. By looking at the slopes, we see that the slope of line 1 is the reciprocal of line 2, and vice versa. Since reciprocal slopes indicate perpendicular lines, the lines 1 and 2 are perpendicular to each other.

Hope this helps!

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At a carry-out pizza restaurant, an order of 3 slices of pizza, 4 breadsticks, and 2 juice drinks costs $13.35. A second order o
BartSMP [9]

Answer: Pizza = $2.95, Breadstick = $0.50, Juice = $1.25

<u>Step-by-step explanation:</u>

Let P represent the cost of a slice of pizza

and B represent the cost of breadstick

and J represent the cost of a juice drink.

EQ1: 3P + 4B + 2J = 13.35

EQ2: 5P + 2B + 3J = 19.50

EQ3: 4B + J = P + 0.30     -->     P - 4B - J = -0.30

Let's eliminate B from EQ1 and EQ2 to form EQ4:

3P + 4B + 2J = 13.35   →  1(3P + 4B + 2J = 13.35)   →   3P + 4B + 2J =  13.35

5P + 2B + 3J = 19.50  → -2(5P + 2B + 3J = 19.50)  →  <u>-10P -  4B -  6J</u> = <u>-39.00</u>

                                                                        EQ4:     -7P          -4J    = -25.65

And eliminate B from EQ1 and EQ3 to form EQ5:

               3P + 4B + 2J = 13.35  

             <u>    P -  4B  - J </u> =<u> -0.30</u>

EQ5:       4P           + J  = 13.05    

Now, eliminate J from EQ4 and EQ5 to solve for P:

-7P  - 4J = -25.65  →    1(-7P  - 4J = -25.65)   →   -7P  - 4J = -25.65

 4P  +  J = 13.05   →    4(4P  +   J =  13.05)    →  <u>  16P  +4J </u>=  <u>52.20</u>

                                                                             9P          = 26.55

                                                                           <u>÷9   </u>           <u>÷9     </u>

                                                                                    P = 2.95

Plug in P = 2.95 into EQ4 or EQ5 to solve for J:

EQ5: 4P + J = 13.05

        4(2.95) + J = 13.05

        11.80 + J = 13.05

                   J = 1.25

Plug in P = 2.95 and J = 1.25 into either EQ1 or EQ2 or EQ3 to solve for B:

EQ3: 4B + J = P + 0.30

        4B + 1.25 = 2.95 + 0.30

        4B + 1.25 = 3.25

                   4B = 2.00

                     B = 0.50

Check (since we used EQ3 to find B, use either EQ1 or EQ2):

EQ2: 5P + 2B + 3J = 19.50

       5(2.95) + 2(0.50) + 3(1.25) = 19.50

       14.75 + 1.00 + 3.75 = 19.50

                            19.50 = 19.50     \checkmark

6 0
3 years ago
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