Write the chemical formula for the cation present in the aqueous solution of cuso4.

1 answer:

4 0

The ionic compounds on dissolving in aqueous solution dissociate into their respective ions that are cations and anions.

The ions present in the aqueous solution of $CuSO_4$ are $Cu^{2+}$ and $SO_{4}^{2-}$ .

So, the chemical formula of the cation present in the aqueous solution of $CuSO_4$ is $Cu^{2+}$ .

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Which phrase change is an endothermic change? (1 point)

Vadim26 [7]

An Endothermic change is a process in which there is absorption of energy.
-Condensation is the transformation from a gas to a liquid. So the water molecules releases energy while condensing, so condensation is exothermic (opposite of endothermic, it's the release of energy)
-Vaporization is the transformation from a liquid to a gas. When you heat water to evaporate it, you're giving energy to the water molecules. And when they absorb this energy, they transform to a gas. Which means that Vaporization is endothermic.
-Deposition is the transformation from gas directly to solid without passing by the liquid phase. Same as the condensation, but the water molecules release even more energy to directly become Solid. So deposition is exothermic.
-Freezing is the transformation from a liquid to a solid. During this phase, water molecules releases energy to its surrounding. So freezing is exothermic.

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5 0

3 years ago

A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h

Ksenya-84 [330]

Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution : 0.0328 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0328=\frac{\text{Number of moles}}{0.250 L}$

Moles of HCl in 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution : 0.0245 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}$

Moles of NaOH in 0.100 L solution = 0.00245 moles

3) Concentration of hydrochloric acid in the resulting solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.

Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L

Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles = 0.00575 moles

$Molarity=\frac{\text{number of moles}}{\text{volume of solution in L}}$

Molarity of HCl left un-neutralized : $\frac{0.00575 moles}{0.350L}=0.0164 M$

0.0164 molar concentration of hydrochloric acid in the resulting solution.

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an atom has 70 protons, 70 electrons, and 99 neutrons. what is the mass number? group of answer choices

Blizzard [7]

Answer:

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