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victus00 [196]
3 years ago
6

Write the chemical formula for the cation present in the aqueous solution of cuso4.

Chemistry
1 answer:
Inessa05 [86]3 years ago
4 0

The ionic compounds on dissolving in aqueous solution dissociate into their respective ions that are cations and anions.

The ions present in the aqueous solution of CuSO_4 are Cu^{2+} and SO_{4}^{2-}.

So, the chemical formula of the cation present in the aqueous solution of CuSO_4 is Cu^{2+}.

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A chef is going to use a mixture of two brands of italian dressing. the first brand contains 9% vinegar, and the second brand co
NikAS [45]

To answer this item, we let x be the amount of the solution that is 9% vinegar in mL and y be the amount of the solution that is 14% vinegar, also in mL. The system of linear equation that would best allow us to answer this item is,

<span>                                    x + y = 290</span>

<span>                                    0.09x + 0.14y = 0.13(290)</span>

<span>The values of x and y in the equations are 58 and 232. Thus, the amounts of the 9% vinegar solution and 14% vinegar solution are 58 and 232 mL, respectively. </span>

4 0
3 years ago
A sample of seawater contains 1.3 g of calcium ions in 3,100 kg of solution. what is the calcium ion concentration of this solut
IrinaVladis [17]

A unit of ppm has an acronym of parts per million. The equivalent units of ppm is therefore mg/L and mg/kg. So the ppm is:

mass Ca+ = 1.3 g = 1300 mg

 

ppm = 1300 mg / 3100 kg

<span>ppm = 0.42 ppm</span>

6 0
3 years ago
Consider this equation: 2.524 g (5.1 × 106 g) ÷ (6.85 × 103 g) = ? How many significant figures should the result have?
weqwewe [10]

Answer:

7

Explanation:

2.524g(5.1)(106)g

(6.85)(103)g

=

1364.4744g2

705.55g

=

1364.4744g

705.55

=

1364.4744g

705.55

=1.933916g

6 0
4 years ago
How would i calculate molecules of water produced in a reaction?
levacccp [35]
You would calculate them by dividing them and then multiplying to get the final answer
5 0
4 years ago
At what celsius temperature does 0.750mol of an ideal gas occupy a volume of 35.9L at 114kPa
pashok25 [27]

Answer:

378.25°C

Explanation:

Given data:

Number of moles of gas = 0.750 mol

Volume of gas = 35.9 L

Pressure of gas = 114 KPa (114/101 = 1.125 atm)

Temperature of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

now we will put the values.

T = PV/nR

T = 1.125 atm × 35.9 L /0.750 mol  × 0.0821 atm.L/ mol.K

T = 40.3875/0.062/K

T = 651.4 K

Kelvin to °C:

651.4 K - 273.15 = 378.25°C

8 0
4 years ago
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