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3 years ago

What is the wavelength, in nm, of radiation which has an energy if 3.371 x 10^-19 joules per photon?

Chemistry

1 answer:

mr_godi [17]3 years ago

5 0

Answer:

The correct option is:

D) 589.3 nm

Explanation:

Energy of one photon = $3.371\times10^{-19}J$

$Energy=\frac{hc}{\lambda}\\\\h=Planck's\:constant=6.626\times10^{-34}J/s\\c=speed\:of\:light=3\times10^{8}m/s\\\lambda=wavelength\:of\:radiation\\\\\lambda=\frac{hc}{Energy}=\frac{6.626\times10^{-34}\times3\times10^{8}}{3.371\times10^{-19}}=5.897\times10^{-7}m=589.7nm\\$

Hence, the wavelength (in nm) of radiation is 589.7nm (approximately equal to 589.3nm)

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A neutral atom has an atomic number of 20 and a mass number of 42. How many electrons does the atom have?

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If we have a neutral atom, then it has the same number protons and neutrons.

The number protons and neutrons for neutral atom shows atomic number.

"A neutral atom has an atomic number of 20" means that atom has 20 protons (that give charge "+ 20" ) and 20 electrons (that give charge "-20").

Answer is 20 electrons.

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3 years ago

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scoray [572]

Answer: Uranium is a chemical element with atomic number 92 which means there are 92 protons and 92 electrons in the atomic structure. The chemical symbol for Uranium is U. Electron configuration of Uranium is [Rn] 5f3 6d1 7s2. Possible oxidation states are +3,4,5,6.

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3 years ago

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Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =

Arada [10]

Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Wherem

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314 J / K mol

Thus, given that, $E_a$ = ?

$k_2=4.0\times 10^3s^{-1}$

$k_1=1.5\times 10^3s^{-1}$

$T_1=5\ ^0C$

$T_2=25\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (5 + 273.15) K = 278.15 K

T = (25 + 273.15) K = 298.15 K

$T_1=278.15\ K$

$T_2=298.15\ K$

So,

$\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)$

$E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}$

$E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}$

$E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}$

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The activation energy for the decomposition = 33813.28 J/mol

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3 years ago

What is the percent composition of carbon in heptane c7h16

Gnom [1K]

Answer: the percent composition of carbon in heptane is 83.9%

Explanation:

1) Atomic masses of the atoms:

C: 12.01 g/mol

H: 1.008 g/mol

2) Molar mass of heptane:

C₇H₁₆: 7 × 12.01 g/mol + 16×1.008 g/mol = 100.2 g/mol

3) Mass of carbon in one mole of heptane:

C₇: 7 × 12.01 g/mol = 84.07 g/mol

3) Percent composition of carbon:

% = (mass in grams of C) / (mass in grams of C₇H₁₆) × 100 =

= (84.07 g/ 100.2 g) × 100 = 83.9% ← answer

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3 years ago

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Answer:

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Explanation:

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