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Alex17521 [72]
3 years ago
10

If 255 J of heat is applied to 20.0 g of

Chemistry
1 answer:
Arisa [49]3 years ago
8 0

Answer:

ΔT  = 98.84 °C

Explanation:

Given data:

Heat absorbed = 255 J

Mass of gold = 20.0 g

Specific heat capacity of gold = 0.129 J/g.°C

Temperature change = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

by putting values,

255 J = 20.0 g × 0.129 J/g.°C × ΔT

255 J  = 2.58 J / °C × ΔT

ΔT  = 255 J  / 2.58 J / °C

ΔT  = 98.84 °C

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A cobalt atom has 27 protons. What number of neutrons would make a cobalt
tamaranim1 [39]
The answers is 54 because 27 protons times theses nuts = 54
7 0
3 years ago
P O R F A V O R
ale4655 [162]

Answer:

a. 45×10³ kg

b. 1.25 kg

c. 5443200 s

d. 2.69×10⁻⁴ m/s²

e. 2.57×10⁻⁶N

f. 7.48×10⁻³ m /s²

g. 2.45 Pa

h. 10 m/s

Explanation:

The SI units are: kg, m, s, N, K, A, Pa, J and cd

a. 1 g is the mass for 1 cm³. We convert the m³ to cm³

45 m³. 1×10⁶ cm³ / 1 m³ = 45×10⁶ cm³

By the way, 45×10⁶ cm³ = 45×10⁶ g

We convert the g to kg →  45×10⁶ g . 1 kg / 1000 g = 45×10³ kg

b. As 1 g = 1 cm³,  we convert the cm³ to g and then, the g to kg

1250 cm³ = 1250 g → 1250 g . 1kg / 1000 g = 1.25 kg

c. 1 day has 24 hours; 1 hour has 60 minutes; 1 minute has 60 seconds

1 hour has 3600 s. Then 24 h . 3600 s / 1 h = 86400 s

86400 s/d. 63 d = 5443200 s

d. 1 min² = 3600 s²

97 cm / 3600 s² = 0.0269 cm/s²  / 100 = 2.69×10⁻⁴ m/s²

e. 927 g.cm / min² / 3600 s² = 0.2575 g.cm/s² → dyn

We need to convert dyn to N

1 dyn = 10⁻⁵N → 0.2575  dyn . 10⁻⁵N / 1dyn = 2.57×10⁻⁶N

f. 1 m/s² = 12960 km/h²

12960 km/h² . 1 m/s² / 97 km/h² = 7.48×10⁻³ m /s²

g. 2500 g/cm² . 1kg / 1000 g = 2.5 kg/cm²

1 Pa = 1.02kg/cm²

2.5 kg/cm² . 1 Pa / 1.02 kg/cm² = 2.45 Pa          

h. 1 h = 3600 s

36 km / 3600 s = 0.01 km /s → 0.01 km . 1000 m / 1 km = 10

= 10 m/s

5 0
3 years ago
what is the concentration of an NaOH solution that requires 50 mL of a 1.25 M H2SO4 solution to neutralize 78.0 ml of NaOH​
Dimas [21]

Answer:

  • The answer is the concentration of an NaOH = 1.6 M

Explanation:

The most common way to solve this kind of problem is to use the formula  

  • C₁ * V₁ = C₂ * V₂

In your problem,

For NaOH

C₁ =??     v₁= 78.0 mL = 0.078 L

For H₂SO₄

C₁ =1.25 M     v₁= 50.0 mL = 0.05 L

but you must note that for the reaction of NaOH with H₂SO₄

2 mol of NaOH raect with 1 mol H₂SO₄

So, by applying in above formula

  • C₁ * V₁ = 2 * C₂ * V₂
  • (C₁ * 0.078 L) = (2*  1.25 M * 0.05 L)
  • C₁ = (2*  1.25 M * 0.05 L) / (0.078 L) = 1.6 M  

<u>So, the answer is the concentration of an NaOH = 1.6 M</u>

3 0
3 years ago
Name an atom that loses one electron when it reacts to another atom
Hitman42 [59]
Lithium, Sodium, Potassium; any of the Alkali Metals, which are farthest left on the periodic table. This is because they only have one electron in their outermost shell, so they would rather lose an electron rather than try to gain 7 to achieve that full outer shell.
4 0
3 years ago
How do subscripts represent the charge balance of ions
finlep [7]
<h3><u>Answer and explanation</u>;</h3>
  • To balance the charges of ions the number of electrons lost is equal to the number of electrons gained. The overall net charge must be zero.
  • The number of ions needed to accomplish this is represented by the subscripts.
  • For any given ionic compound, the product of the charge on the ion (or multiatomic ionic group) times the subscript of the ion will give a total charge of zero when all ions are considered.

For examples: NaCl Na = +1 Cl = -1 total is zero

5 0
4 years ago
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