If 255 J of heat is applied to 20.0 g of
1 answer:
Answer:
ΔT = 98.84 °C
Explanation:
Given data:
Heat absorbed = 255 J
Mass of gold = 20.0 g
Specific heat capacity of gold = 0.129 J/g.°C
Temperature change = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
by putting values,
255 J = 20.0 g × 0.129 J/g.°C × ΔT
255 J = 2.58 J / °C × ΔT
ΔT = 255 J / 2.58 J / °C
ΔT = 98.84 °C
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