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Sati [7]
3 years ago
10

A precipitation reaction is caused by mixing 100. mL of 0.25 M K2Cr2O7 solution with 100. mL of 0.25 M Pb(NO3)2 solution. When t

he precipitate forms, it is filtered from the mixture.What is the concentration of nitrate anion in the reaction mixture after filtration?0.50 M0.10 M0.0 M0.25 M
Chemistry
1 answer:
pav-90 [236]3 years ago
4 0

Answer:

The molarity of the nitrate ion = 0.25 M

Explanation:

<u>Step 1:</u> Data given

Volume of 0.25 M K2Cr2O7 = 100 mL = 0.1 L

Volume of 0.25 M Pb(NO3)2 =100 mL = 0.1 L

<u>Step 2:</u> The balanced equation

Pb(NO3)2(aq) + K2Cr2O7(aq) → PbCr2O7(s) + 2KNO3(aq)

PbCr2O7(s) + 2KNO3(aq) → PbCr2O7(s) + 2K+ + 2NO3-

<u>Step 3:</u> Calculate moles of K2Cr2O7

Moles K2Cr2O7 = Molarity K2Cr2O7 * volume

Moles K2Cr2O7 = 0.25M * 0.1 L

Moles K2Cr2O7 = 0.025 moles

<u>Step 4:</u> Calculate moles of Pb(NO3)2

Moles Pb(NO3)2  = 0.25 M * 0.1 L

Moles Pb(NO3)2  = 0.025 moles

<u>Step 5</u>: Calculate limiting reactant

For 1 mol Pb(NO3)2 consumed, we need 1 mol of K2Cr2O7, to produce 1 mol of PbCr2O7 and 2 moles of KNO3

Both reactant will be completely consumed. since there will react 0.025 moles of both.

<u>Step 6: </u>Calculate moles of KNO3

For 1 mol Pb(NO3)2 consumed, we need 1 mol of K2Cr2O7, to produce 1 mol of PbCr2O7 and 2 moles of KNO3

For 0.025 mol Pb(NO3)2, we have 2*0.025 = 0.050 moles of KNO3

<u>Step 7:</u> Calculate moles of nitrate ion

2 moles KNO3 will dissociate in 2 moles of K+ and 2 moles of NO3-

For 0.050 moles KNO3, we'll have 0.050 moles of NO3-

<u>Step 8</u>: Calculate molarity of NO3- ion

Molarity NO3- = moles NO3- / volume

Molarity NO3- = 0.050 moles/ 0.2L

Molarity NO3- = 0.25 M

The molarity of the nitrate ion = 0.25 M

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