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Oliga [24]
3 years ago
10

How long will it take for a 750 mg sample of radium with a half life of 15 days to decay to exactly 68mg?

Chemistry
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

52 da  

Step-by-step explanation:

Whenever a question asks you, "How long to reach a certain concentration?" or something similar, you must use the appropriate integrated rate law expression.

The i<em>ntegrated rate law for a first-order reaction </em>is  

ln([A₀]/[A] ) = kt

Data:

[A]₀ = 750 mg

 [A] =    68 mg

t_ ½ =   15 da

Step 1. Calculate the value of the rate constant.

 t_½ = ln2/k     Multiply each side by k

kt_½ = ln2         Divide each side by t_½

      k = ln2/t_½

         = ln2/15

         = 0.0462 da⁻¹

Step 2. Calculate the time

ln(750/68) = 0.0462t

         ln11.0 = 0.0462t

            2.40 = 0.0462t     Divide each side by 0.0462

                   t = 52 da

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Answer:

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The electrolyte of copper (II) sulfate CuSO₄ solution

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The drawing of the electrolytic cell created with Microsoft Visio is attached

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3 years ago
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Answer:

mass of Liquid 1 + mass of Liquid 2 = mass of solid + mass of gas

Explanation:

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7 0
3 years ago
Why is it preferable to allow cold water to enter at the bottom of a condenser and exit at the top?
harkovskaia [24]
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4 years ago
What is the symbol of the new atom?<br><br>Also, is the atomic number 86?
katrin [286]

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3 years ago
Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

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The amount of calcium is: (i.e formula mass of calcium)

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The amount of hydrogen is:

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So, the percentage component of hydrogen is:

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The amount of oxygen is:

E = 2 * O

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\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

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