Minimum: 63
maximum: 99
median: 79
hope this helps
Answer:the horizontal displacement is 34.64 meters
The maximum height is 15 meters
Step-by-step explanation:
As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is
R = U^2Sin2#)/g
Where
U represents the initial velocity of the ball
g is acceleration due to gravity
# represents the angle above the horizontal.
From the information given
# = 30 degrees
U = 20 m/s
g = 10m/s^2
R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10
= 34.64 meters
To determine the maximum height of the ball, H,
H = (U^2Sin^2#)/2g
H = (20^2 × Sin^2 30)/2×10
H = (400 × 0.866^2)/20 = 15 meters
Answer:
Growth: 3
y-intercept: 5
Step-by-step explanation:
1. Find the equation in slope-intercept form:
-6x+2y=10
2y=6x+10
y=3x+5
2. Then we can easily identify the growth and y-intercept.
Growth: 3
y-intercept: 5
We know that
<span>An<span> exterior angle</span></span><span> is one that has its vertex at an outer point of the circumference
</span><span>The measure of the external angle is the semidifference of the arcs that it covers
</span>
so
∠NOP=(70-30)/2-----> 20°
the answer is
<span>∠NOP=20</span>°