Answer:
B. 0.42
Explanation:
Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1
According to the given information, the frequency of one allele in the population is= 0.7
This means that the frequency of the other allele would be= 1-0.7 = 0.3
Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42
Answer:
During telophase nuclear membrane is formed, nucleolus appears and astral rays disappear.
During telophase, the effects of prophase and prometaphase - the nuclear membrane and nucleolus disintegrating are reversed. Two daughter nuclei form in each daughter cell, and phosphatases dephosphorylate the nuclear lamins at the ends of the cell, forming nuclear envelopes around each nucleus.
<span>The control would be a plant grown without any fertilizer. This is called a negative control and is important in identifying the influence of the treatments on the tests. In this case, it would mean that the plant without fertilizer (control) is not expected to grow as large as in the other treatment. </span>
The correct answer is
Stasis
Population becomes isolated
After rapid change in isolated population
Reintroduction
