The limiting reactant is determined by the supply and stoichiometric equation.
<h3>Limiting reactants</h3>
They are reactants that are limited in availability, and thus, determine how far reactions can go in terms of producing products.
In a reaction involving magnesium and hydrochloric acid to produce hydrogen gas as follows:

The number of moles of HCl is twice that of Mg. Thus, if both reactants are supplied in the required proportion, no reactant will be limiting.
However, if the number of moles of HCl supplied is not up to twice that of Mg, HCl will become limiting. Also, if the amount of Mg supplied is not equal to half of that of HCl supplied, Mg will be limiting.
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Answer:
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Answer is: dissolve 74,9 grams CuSO₄·5H₂O in one liter volumetric flask.
V(CuSO₄·5H₂O) = 1 L.
c(CuSO₄·5H₂O) = 0,30 mol/L.
n(CuSO₄·5H₂O) = V(CuSO₄·5H₂O) · c(CuSO₄·5H₂O) .
n(CuSO₄·5H₂O) = 1 L · 0,3 mol/L.
n(CuSO₄·5H₂O) = 0,3 mol.
m(CuSO₄·5H₂O) = n(CuSO₄·5H₂O) · M(CuSO₄·5H₂O).
m(CuSO₄·5H₂O) = 0,3 mol · 249,7 g/mol.
m(CuSO₄·5H₂O) = 74,9 g.
In flame tests salts<span> that are </span>dissolved in water<span> are evaporated using a </span>hot flame<span>. In the flame the </span>metal atoms<span> become excited and produce their characteristic spectrum of light. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>