The answer is CI because that is the largest
Answer:
T₂ = 169.89 K
Explanation:
Given data:
Initial volume = 250 cm³
Initial temperature = 10°C (10+273.15 K = 283.15 K)
Final temperature = ?
Final volume = 150 cm³
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂/V₁
T₂ = 283.15 K × 150 cm³ / 250 cm³
T₂ = 42472.5 K. cm³ / 250 cm³
T₂ = 169.89 K
The half life of an isotope is the amount of time it will take for the given isotope to decay till the point where it reaches half of what amount you had started with.
If the half life of Ra-229 is 4 minutes then every 4 minutes the sample is reduced to half of what you had before
4 minutes.) 50/2 Ra-229 --> 25g Ra-229
8 minutes.) 25/2 Ra-229 --> 12.5 Ra-229
12 minutes.) 12.5/2 Ra-229 --> 6.25 Ra-229 remaining
<em>I beleive this is the correct answer</em>
Answer:
7.67578 ml
Explanation:
assuming the missing information
Conc. of nitric acid = 70.3% by mass
density =1.41 g/ml
Now, moles of HNO3 required = final volume× final conc.
= 1.15×0.105= 0.12075 mol
Mass of HNO3 required = moles×molar mass of HNO3
= 0.12075×63.01=7.6084575 g
mass of solution = 100/70.3 of 7.6084575
=10.82284 g
therefore, volume of the solution = mass/density
= 10.82285/1.41
= 7.67578 ml
