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Neporo4naja [7]
2 years ago
14

Which symbol represents an atom in the ground state with the most stable valence electron configuration?

Chemistry
2 answers:
qwelly [4]2 years ago
6 0

Answer: Ne

Explanation: The stable valence configuration is one in which the orbitals are completely filled as they are least reactive. Elements with partially filled valence shells are less stable and more reactive as they tend to gain or lose electrons to acquire stability.

Boron:B:5:1s^22s^22p^1

Lithium:Li:3:1s^22s^1

Oxygen:O:8:1s^22s^22p^4

Neon:Ne:10:1s^22s^22p^6

Anestetic [448]2 years ago
3 0
Ne is the symbol representing an atom in the ground state with the most stable valence electron configuration
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A 99.8 mL sample of a solution that is 12.0% KI by mass (d: 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0% Pb
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Hello,

In this case, we write the reaction again:

Pb(NO_3)_2(aq) + 2 KI(aq)\rightarrow PbI_2(s) + 2 KNO_3(aq)

In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:

n_{Pb(NO_3)_2}=\frac{0.14gPb(NO_3)_2}{1g\ sln}*\frac{1molPb(NO_3)_2}{331.2gPb(NO_3)_2}  *\frac{1.134g\ sln}{1mL\ sln} *96.7mL\ sln\\\\n_{Pb(NO_3)_2}=0.04635molPb(NO_3)_2\\\\n_{KI}=\frac{0.12gKI}{1g\ sln}*\frac{1molKI}{166.0gKI}  *\frac{1.093g\ sln}{1mL\ sln} *99.8mL\ sln\\\\n_{KI}=0.07885molKI

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m_{PbI_2}=0.07885molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gPbI_2

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