Answer:
Option D that is y=-2(x+1) is the correct choice.
Explanation:
Given equation:
We have to find another equation which has only one solution.
Standard form of equation:


Condition for one solution.

We have to arrange other equation in the form of 
Mark all the options as a,b,c and d.




Now from the above options we can see that option
are not providing the desired result.
So
can be obtained from the last option.
As

Option D that is
is the equation from where we can obtained only one solution.
It's 67/4=16.75
your answer is 16.75
Answer: -4 is the answer
Step-by-step explanation: google caculator
ANSWER
The probability that someone owns an iPhone or an Apple watch is

or

EXPLANATION
We were given that, the probability that someone owns an iPhone is

and the probability that someone owns Apple watch is

and the probability that someone owns both is

Since the intersection is not zero, it means the two events are not mutually exclusive.
The probability that someone owns an iPhone or Apple phone is

We substitute the values to get,

Answer:
25272 to the 10 power
Step-by-step explanation: