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True [87]
3 years ago
10

Graph the inequality y > 3x + 3

Mathematics
1 answer:
natita [175]3 years ago
7 0

Answer:

see below

Step-by-step explanation:

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$28,000 invested at a rate of 4% compounded annually; 5 years
sasho [114]
$28<span> compounded on a </span>Yearly<span> basis over the course of </span>5<span> years at a </span>4% interest rate would be worth:

<span>$34</span>
4 0
3 years ago
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What is the IQR (interquartile range) of the data set? 33, 37, 45, 61, 64, 67
Nataly_w [17]

solution is first os all find median

median is( 45+61)/2=53

find median of no in left of 53

it is 37

find median of no in right of 53

it is 64

now interquartile range=64-53=27

4 0
3 years ago
Solve.<br> <img src="https://tex.z-dn.net/?f=2%205%2F6%20%2B%20%28-1%204%2F12%29%20%3D" id="TexFormula1" title="2 5/6 + (-1 4/12
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Step-by-step explanation:

5 0
2 years ago
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A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
I need this ASAP please
adelina 88 [10]

Answer:

m>2 is the correct answer

5 0
3 years ago
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