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tatyana61 [14]
3 years ago
10

A group of adults and students buy tickets for a dance performance.

Mathematics
1 answer:
kakasveta [241]3 years ago
6 0

Answer:

There are 10 students

Step-by-step explanation:

69.55-(5.35*3)= 53.5

53.5/10=5.35 which is what each ticket costed

So the answer is 10 students

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Help me plz show work​
FinnZ [79.3K]

Answer:

c. 2,320miles

Step-by-step explanation:

29 divided by 1/4 = 116

116*20=2,320

7 0
3 years ago
Write an equation in point-slope form of the line having the given slope that contains the given point. then graph the line
alexira [117]
The point-slope equation would be
y = 1/8x + 3/4
3 0
3 years ago
Read 2 more answers
X solve for the following inequality-1/2 p less than -16 which graph shows the correct solution
valkas [14]

Answer:

See attachment

Step-by-step explanation:

The given inequality is

-  \frac{1}{2}p \: <  \:  - 16

We multiply both sides by -2 and reverse the inequality sign to get:

- 2 \times  -  \frac{1}{2} p \:   >  \:  - 2 \:  \times  - 16

p \:  >  \: 32

We draw an open circle at 32 and draw an arrow to the right as shown in attachment.

8 0
3 years ago
Read 2 more answers
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
What are four consecutive odd integers that equals 184
Serggg [28]

1st: 2x-3  2nd: 2x-1 3rd: 2x+1 4th: 2x+3

adding the above you get 8x=184

3 0
3 years ago
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