Consider the line y=-3x+1.
1 answer:
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The equation of line parallel to and containing the point(-10,-3) is
Step-by-step explanation:
We need to write the equation parallel to and containing the point(-10,-3)
The standard form of point slope equation is:
where m is slope and b is y-intercept
Comparing the given equation with standard form the slope is m= -1/5
Since the lines are parallel the slope of new line is m = -1/5
Now finding b (y-intercept)
Using slope m=-1/5 and point (-10,-3)
So, b= -5 and slope = -1/5 the equation of new line is:
So, The equation of line parallel to and containing the point(-10,-3) is
Keywords: Point Slope form
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The equation of the line that is parallel to the given line and passes through the point (-2,2) is:
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
When two lines are parallel, they have the same slope. In this problem, the given line passes through (-5,-4) and (0,-3), hence the slope is:
m = (-3 - (-4))/(0 - (-5)) = 1/5.
Hence the equation is:
When x = -2, y = 2, then:
Hence:
More can be learned about linear equations at brainly.com/question/24808124
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