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Tamiku [17]
3 years ago
9

I’m timed!!!! Help me!

Mathematics
2 answers:
k0ka [10]3 years ago
5 0

Answer:

12

Step-by-step explanation:

qwelly [4]3 years ago
3 0

Answer:

6

Step-by-step explanation:

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PLEASE HELP precal!
sergij07 [2.7K]
Check the picture below

so.. .hmmm the vertex is at the origin... and we know the parabola passes through those two points... let's use either.. say hmmm 100,-50, to get the coefficient "a"

keep in mind that, the parabolic dome is vertical, thus we use the y = a(x-h)²+k  version for parabolas, which is a vertical parabola

as opposed to x = (y-k)²+h, anyway, let's find "a"

\bf y=a(x-0)^2+0\implies y=ax^2\qquad 
\begin{cases}
x=100\\
y=-50
\end{cases}\implies -50=a100^2
\\\\\\
\cfrac{-50}{100^2}=a\implies -\cfrac{1}{200}=a
\\\\\\
thus\qquad \qquad y=-\cfrac{1}{200}x^2\implies \boxed{y=-\cfrac{x^2}{200}}

now.. .your choices, show.... a constant on the end.... a constant at the end, is just a vertical shift from the parent equation, the equation we've got above.. is just the parent equation, since we used the origin as the vertex, it has a vertical shift of 0, and thus no constant, but is basically, the same parabola, the one in the choices is just a shifted version, is all.


5 0
3 years ago
Linear equation 3+X=-2 ​
lyudmila [28]

Answer:

x = -5 ​

Step-by-step explanation:

3+X=-2 ​

Subtract 3 from each side

3-3+X=-2-3

x = -5 ​

4 0
3 years ago
Read 2 more answers
In what positive integral number base is 231 double 113
ad-work [718]

Answer:

Base 5

Step-by-step explanation:

We want to determine the base at which:

113 X 2 =231

We consider the last number of the result (231).

The base must be a number such that:

3 X 2 will have a remainder of 1.

3 X 2 = 6 = 5 Remainder 1

Therefore:

113 X 2 =231 in positive integral number base 5.

5 0
3 years ago
Consider the following frequency distribution.
Zarrin [17]

Answer:

Class interval                            10-19 20-29 30-39 40-49 50-59

cumulative frequency               10      24       41        48       50

cumulative relative frequency 0.2   0.48     0.82    0.96      1

Step-by-step explanation:

1.

We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.

Cumulative frequency

10

10+14=24

14+17=41

41+7=48

48+2=50

sum of frequencies is 50 so the relative frequency is f/50.

Relative frequency

10/50=0.2

14/50=0.28

17/50=0.34

7/50=0.14

2/50=0.04

Cumulative relative frequency

0.2

0.2+0.28=0.48

0.48+0.34=0.82

0.82+0.14=0.96

0.96+0.04=1

The cumulative relative frequency is calculated using relative frequency.

Relative frequency is calculated by dividing the respective frequency to the sum of frequency.

The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.

The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.

4 0
3 years ago
What does 6 - 6 + 3 =
Mice21 [21]

Answer:

3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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